Parsing out string values in Ruby

Question

I have a ruby string car_1_ford I want the out put to be

car 1 ford

what is the best way in ruby to parse this string?

Do you want 'car 1 ford' or ['car', '1', 'ford'] as your result? — mu is too short
– mu is too short, Commented Dec 23, 2011 at 22:31

Jordan Running · Accepted Answer · 2011-12-23 22:00:38Z

6

string = "car_1_ford"

string.gsub!("_", " ")

edited Dec 23, 2011 at 22:00

Jordan Running

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answered Dec 23, 2011 at 21:58

ennuikiller

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Comments

Sergio Tulentsev · Accepted Answer · 2011-12-23 22:02:20Z

2

If you're trying to break that string into 3 pieces, then use this code

s = 'car_1_ford'
s.split('_')

(oh, there's ^ an emoticon :-) )

Result will be this

['car', '1', 'ford']

answered Dec 23, 2011 at 22:02

Sergio Tulentsev

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Comments

Andrzej Gis · Accepted Answer · 2011-12-23 22:13:43Z

1

If you'll ever need some more advanced patterns you can use regular expressions.

Here you have Documentation.

Example:

irb(main):012:0> "a_b----c==d".gsub!(/[-_=]+/, ' ')
=> "a b c d"

answered Dec 23, 2011 at 22:13

Andrzej Gis

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Comments

steenslag · Accepted Answer · 2011-12-23 22:27:39Z

0

"car_1_ford".tr('_', ' ') #=> "car 1 ford"

If you only substitute a character for another character then the #tr method is nice, and it alows for multiple changes in one go:

"car_1_ford#model T".tr('_#', ' :') #=> "car 1 ford:model T"

answered Dec 23, 2011 at 22:27

steenslag

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