Array of structs returns errors

Question

I have the following code:

static int gridX = 40;
static int gridY = 40;

public struct CubeStruct
{
    public Transform cube;
    public bool alive;
    public Color color;
}

public CubeStruct cubeArray[,] = new CubeStruct[gridX, gridY];

This returns the following errors:

error CS1519: Unexpected symbol `,' in class, struct, or interface member declaration

error CS0178: Invalid rank specifier: expected ,' or]'

error CS1519: Unexpected symbol `;' in class, struct, or interface member declaration

It's probably something obvious, but I can't see it.

Sergey Kalinichenko · Accepted Answer · 2011-12-26 12:21:34Z

5

In C#, the [,] go before the name of the variable (i.e. it is not like in C/C++).

public CubeStruct[,] cubeArray = new CubeStruct[gridX, gridY];

answered Dec 26, 2011 at 12:21

Sergey Kalinichenko

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1 Comment

Simon Verbeke Over a year ago

I'm quite ashamed that I missed it.. Thanks!

TehBoyan · Accepted Answer · 2011-12-26 12:21:46Z

5

public CubeStruct cubeArray[,] = new CubeStruct[gridX, gridY];

should be:

public CubeStruct[,] cubeArray = new CubeStruct[gridX, gridY];

answered Dec 26, 2011 at 12:21

TehBoyan

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Comments

Adam · Accepted Answer · 2011-12-26 12:29:21Z

3

~~In C#, nothing can float around outside of a Type. So you need to do this:~~
Also note that the [,] comes after the type, not after the identifier.

public class GridMain
{
    static int gridX = 40;
    static int gridY = 40;
    public CubeStruct[,] cubeArray = new CubeStruct[gridX, gridY];

}

public struct CubeStruct
{
    public Transform cube;
    public bool alive;
    public Color color;
}

edited Dec 26, 2011 at 12:29

answered Dec 26, 2011 at 12:24

Adam

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2 Comments

Simon Verbeke Over a year ago

Of course, my code is IN a class. I just copy/pasted the relevant bit.

Adam Over a year ago

sure, that wasn't clear from your question. Thanks for clarifying.

Roee Gavirel · Accepted Answer · 2011-12-26 12:26:57Z

2

change:

public CubeStruct cubeArray[,] = new CubeStruct[gridX, gridY];

to:

public CubeStruct[,] cubeArray = new CubeStruct[gridX, gridY];

edited Dec 26, 2011 at 12:26

answered Dec 26, 2011 at 12:21

Roee Gavirel

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