JQuery Combining Variable With String

Question

I'm trying to make the following work but can't figure out how to combine variables with string. I've commented the areas I don't understand below.

Thank you!

$('.mcTransferGroup').each(function() {
    var mcAdd = $(this).find('#mcAdd');
    var mcRemove = $(this).find('#mcRemove');
    var mcSelect1 = $(this).find('.mcSelect1');
    var mcSelect2 = $(this).find('.mcSelect2');

    $(mcAdd).click(function() {
        // below here
        $(mcSelect1, 'option:selected').remove().appendTo(mcSelect2);
    });
    $(mcRemove).click(function() {
        // and here ...
        $(mcSelect2, 'option:selected').remove().appendTo(mcSelect1);
    });
});

Why return in the event handler?

sje397
– sje397

2011-12-27 11:31:42 +00:00
Commented Dec 27, 2011 at 11:31 — sje397
– sje397, Commented Dec 27, 2011 at 11:31

sje397 · Accepted Answer · 2011-12-27 11:37:29Z

1

Try e.g.:

$('option:selected', mcSelect1).remove().appendTo(mcSelect2);

The context should be the second argument.

Here's an example: http://jsfiddle.net/ZbZx9/

answered Dec 27, 2011 at 11:37

sje397

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Comments

oryol · Accepted Answer · 2011-12-27 11:34:46Z

0

Use http://api.jquery.com/find/ (for finding element inside given element) and http://api.jquery.com/filter/ (to filter existing jQuery selection).

answered Dec 27, 2011 at 11:34

oryol

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2 Comments

user1002039 Over a year ago

But how do I combine a variable with a filter? The manual says nothing about it.

oryol Over a year ago

If mcSelect1 is select tag - use mcSelect1.find('...'). If it's already option collection (I can't be sure what it is because you didn't provide HTML code) - use mcSelect1.filter('...').

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