Search if any element of array found in another array in PHP

Question

How can I search an element of an array in another array? If any element is found, the search function returns true, else it returns false.

For example:

$mainArray = array(1,2,3,4,5);
$tosearch = array(2,7); //returns true as 2 is in main array.
$tosearch = array(7,8); //return false as no element found in main array.

score 4 · Accepted Answer · 2011-12-31 21:00:34Z

4

var_dump((bool) array_intersect($arr1, $arr2));

EDIT

Just to clarify my answer ... since you are looking for TRUE or FALSE, I include a boolean typecast (bool). Without the cast, array_intersect will return a truthy array, but still an array.

edited Dec 31, 2011 at 21:00

answered Dec 31, 2011 at 20:49

user895378

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rabusmar · Accepted Answer · 2011-12-31 20:47:00Z

2

You can use array_intersect for that, like this:

if (array_intersect($mainArray, $tosearch)) {
    // elements in common
}

answered Dec 31, 2011 at 20:47

rabusmar

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1 Comment

Shehzad Bilal Over a year ago

Thanks,, it work,, i didnt know that PHP got a builtin function for that.

Ben D · Accepted Answer · 2011-12-31 20:48:00Z

0

Are you sure you're working in PHP, or is your array syntax just for illustration?

In any case, look at the array_intersect() function:

http://php.net/manual/en/function.array-intersect.php

answered Dec 31, 2011 at 20:48

Ben D

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