How can I declare an array of byte arrays with a limited size for the array? This is what I was thinking but it's not working and I couldn't find anything.
private Integer number =10000;
private byte[] data[];
data = new byte[][number];
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2 Answers
Something like this?
private byte[][] data; // This is idiomatic Java
data = new byte[number][];
This creates an array of arrays. However, none of those sub-arrays yet exist. You can create them thus:
data[0] = new byte[some_other_number];
data[1] = new byte[yet_another_number];
...
(or in a loop, obviously).
Alternatively, if they're all the same length, you can do the whole thing in one hit:
data = new byte[number][some_other_number];
answered Jan 1, 2012 at 21:04
Oliver Charlesworth
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5 Comments
gtdevel
Yes. Exactly. Just to clarify, does that mean that I will have "number" byte arrays, each with an undetermined size?
Oliver Charlesworth
@gtdevel: In that first code snippet, you will have an array of length
number. Each element of that array is a reference to a byte array, and is initialised to null. i.e. data[0] == null is true.Oliver Charlesworth
@Zéychin: Not exactly. See my above comment; it means you have "number" references to byte arrays; the byte arrays don't actually exist yet.
gtdevel
@OliCharlesworth I understand what you are saying. Thanks.
Zéychin
@OliCharlesworth: You are correct. I've forgotten my place, as I too often discuss these sorts of things with people who know these details and so there it is often acceptable to omit them in description for brevity. +1 for the correction for the clarity of the original poster.
may be you need a 2-d array
private byte[][] data = new byte[10][number];
that declares 10 byte arrays each of size number
