Error when passing argument to a command in a bash script

Question

I would like to execute a command like this:

#!/bin/sh
`which rvmsudo` `which program` argument

but I get this issue

/usr/bin/env: argument: No such file or directory

You want to pass the argument you give to the script as the argument to the command inside the script? Then you should change the argument to $1 — Raghuram
– Raghuram, Commented Jan 2, 2012 at 10:37
unrelated to your error but you must use #!/bin/bash if you really want bash, otherwise your script will run in compatibility mode (POSIX) — Samus_
– Samus_, Commented Jan 2, 2012 at 21:36

Eugen Rieck · Accepted Answer · 2012-01-02 10:40:55Z

2

Make sure, all of the which statements return valid:

#!/bin/bash

RVMSUDO=`which rvmsudo`
test -z "$RCMSUDO" && exit 1

PROGRAM=`which program`
test -z "$PROGRAM" && exit 2

$RVMSUDO $PROGRAM argument

answered Jan 2, 2012 at 10:40

Eugen Rieck

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