Rails Javascript if else condition using variable from Controller

Question

View

<%= link_to "Link", {:action => "AjaxView",:col => "colname"}, 
            :update => "Ajaxcall", :remote => true %>

Controller

  def AjaxView
    @vars= Var.find(:all,:conditions => { :varName=> "one" },:select=>(params[:col]))
    respond_to do |format|
      format.js { render :layout=>false }
    end
  end

AjaxView.js.erb

   if ( (<%= col %>) == "colName") {
     $("#3").text("<%= escape_javascript(render(:partial => "var") %>");
   }
   else
   {
     $("#2").text("<%= escape_javascript(render(:partial => "var") %>");
   }

Issue here is this Variable "col" doesn't get its exact value in AjaxView.js.erb file, and my If else condition doesn't get executed. What am i missing here ?

side note: the modern approach is to get JSON (not JS code) and let JS (in the client) update the view. — tokland
– tokland, Commented Jan 2, 2012 at 13:32
@amit don't replicate questions stackoverflow.com/questions/8712852/… — RAJ
– RAJ, Commented Sep 26, 2012 at 12:14

Jesse Storimer · Accepted Answer · 2012-01-02 13:10:28Z

0

The local variable col isn't assigned in AjaxView.js.erb. I think you meant to write it as params[:col].

Also the double quotes around var should be single quotes, to play nice with the surrounding double quotes.

answered Jan 2, 2012 at 13:10

Jesse Storimer

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1 Comment

Amit Vashistha Over a year ago

is tried with params[:col] in my if condition, but it didn't worked.

Robin · Accepted Answer · 2012-01-02 13:15:49Z

0

{:action => "AjaxView",:col => "colname"}

This is not how you build a url for link_to.

What's the route to access the AjaxView method?
It should be something like: link_to "Link", AjaxView_resources_path(:col => "colname").

And in your controller, you need to set an instance variable @col = params[:col] to be able to use it in your view.

ps: your should name your method ajax_view instead of AjaxView.

answered Jan 2, 2012 at 13:15

Robin

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9 Comments

Amit Vashistha Over a year ago

Thanks @Robin for your reply, when I put "( @ col = params[:col])" in controller and in AjaxView.js.erb when I run this " (if ( (<%= @ col %>) == "colName"))", it still didn't worked.

Robin Over a year ago

The thing is, with the way you build your link, I don't even know how your action gets executed...

Amit Vashistha Over a year ago

lot of people have doubted that, some even suggested that I should start using form instead of link, there are blogs written on this, but somehow i was able to run this without any issue. And it works for me, only issue here that I am facing now is to try with multiple options, and for that I have to run if condition in .js.erb file, if you could help me running this, I will be really thankful. I am almost done with my work.

Amit Vashistha Over a year ago

Also, AjaxView_resources_path(:col => "colname") is same as {:action => "AjaxView",:col => "colname"} just the way of writing is different, whatever I am writing in curly bracket goes as a HTML input.

Robin Over a year ago

I dont think it is... How is rails supposed to know about which controller to use? Also, I can't see why you would need a form. A link is fine in this case.

|

Amit Vashistha · Accepted Answer · 2012-02-04 16:53:09Z

0

  if ( @col.to_s == "colName") {
      $("#3").text("<%= escape_javascript(render(:partial => "var") %>");
     }
      elsif ( @col.to_s == "colName1")
     {
     $("#2").text("<%= escape_javascript(render(:partial => "var") %>");
     }

answered Feb 4, 2012 at 16:53

Amit Vashistha

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