Jquery ajax variables into php

Question

Hi i'm trying to retrieve response after passing some variables from javascript to php using jquery ajax functions.

This is the jquery ajax code:

$(document).ready(function() {

    $("#invoice_submit_button").click(function() {

        var action = $("invoice_form").attr('action');

        $.ajax({
            type: "POST",
            url: action,
            data: $('form#invoice_form').serialize(),
            dataType: "json",
            success: function(response) {
                if (response.error == 'none') {
                    $("#ajax_response").html("<p>" + response.msg + "</p>");
                }
                else {

                    $("#ajax_response").html("<p>" + response.msg + "</p>");

                }
            }
        });

        return false;
    });
});

(ofc there will be different outputs depending on the response.error when get it to work, it's just an example)

This is the php code:

$msg="Bla bla";
$error="form_err";
$result = array('msg' => $msg, 'error' => $error);
$result_json = json_encode($result);
echo $result_json;

Debugging using firebug shows that there're not issues with the posting part but it looks like the script can't get a response from php(and print it into the target div). I'm missing something, i used the same method for other scripts and it has always worked. Thanks

action is empty as jQuery cannot find an element invoice_form. $("invoice_form").attr('action'); should be $("#invoice_form").attr('action');. Are you sure the request is sent to the correct URL? — Felix Kling
– Felix Kling, Commented Jan 2, 2012 at 16:28
Great, thanks. I lost the # copy pasting from an old script. edit: can't i rep or whatever comments? — g0dl3ss
– g0dl3ss, Commented Jan 2, 2012 at 16:48
I provided my comment as an answer so that you can accept it. — Felix Kling
– Felix Kling, Commented Jan 2, 2012 at 16:51

MobileSam · Accepted Answer · 2012-01-02 16:28:38Z

1

Have you tried to set the content type to application/json in your PHP script?

header('Content-type: application/json');

answered Jan 2, 2012 at 16:28

MobileSam

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1 Comment

Felix Kling Over a year ago

Will probably not make any difference.

Felix Kling · Accepted Answer · 2012-01-02 16:51:52Z

0

action is empty as jQuery cannot find an element invoice_form.

$("invoice_form").attr('action'); should be $("#invoice_form").attr('action');.

Are you sure the request is sent to the correct URL?

answered Jan 2, 2012 at 16:51

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