I need to write an array that looks like this:
$years = array('12', '11', '10', '09', '08');
I would like to have a script that will create this array, so that I don't have to update it every year.
Tried this:
for ($i = date("y"); $i >= 08; $i++) {
$yrs .= '"'.$i.'", ';
}
$years = array($yrs);
You want to decrement in your loop instead of increment, since you are trying to go from 12 down to 8. So change your ++ to --. You can also append to an array using the $years[] = ... notation, and make an array using $years = array():
$years = array();
for ($i = date("y"); $i >= 8; $i--)
$years[] = str_pad($i, 2, "0", STR_PAD_LEFT);
print_r($years) gives:
Array
(
[0] => 12
[1] => 11
[2] => 10
[3] => 09
[4] => 08
)
Example: http://codepad.viper-7.com/VDQNj2
08, but doesn't because you prefixed the number 8 with a zero, causing it to be interpreted as an octal number. However, since 8 is an invalid digit for an octal number, it gets converted to the integer value 0. To fix it, just remove the 0! :)
$years = array();
for ($i = date("y"); $i >= 8; $i--) {
$years[] = substr("00".$i,-2);
}
PHP's range function helps out a lot here:
$thisYear = date('Y'); // "2012"
$years = range($thisYear, $thisYear-4);
// array(2012,2011,2010,2009,2008)
$thisYear = date('y'); // "2012"
$years = range($thisYear, $thisYear-4);
// array(12,11,10,9,8)
$years = array_map(function($year) {
return sprintf('%02u', $year);
}, $years);
// array("12","11","10","09","08")
Note: The use of an inline function (closure) for array_map requires PHP 5.3+
