I have a question, that i am getting a JSON response from a by calling a service, i am getting the name, location, position, email, phone number field. Each field is stored in its ArrayList. and i am showing these value in Listview.
Now i have to show the Name in sorted order, but other fields should also get arranged by corresponding name.
We can do by sorting by using Collection.sort(nameArrayList), but how other field will get affected?? how to do this in efficient way?? Any idea??
Thanks.
create a hashMap<String name ,pojo values) ;
now read every name and store corresponding values location, position, email, phone number into pojo object .
map.put(name , pojo) ;
after inserting all values sort map by name . wherever using hashmap to populate list , iterate over keys and value and use them
When name is repeated
better to use ArrayList with your own comparator . go through this code snippet for more help
public class Main {
String name = null;
// 2011-12-11 11:30:20:0
public static void main(String[] args) {
ArrayList<Main> main = new ArrayList<Main>();
main.add(new Main("CRohit"));
main.add(new Main("DRohit"));
main.add(new Main("ARohit"));
main.add(new Main("12349"));
main.add(new Main("BRohit"));
main.add(new Main("ZRohit"));
main.add(new Main("12345"));
main.add(new Main("FRohit"));
main.add(new Main("12348"));
main.add(new Main(null));
main.add(new Main(null));
Collections.sort(main, new PojoComparator());
for(Main m : main)
{
System.out.println(m.getName());
}
}
public Main(String name)
{
this.name = name;
}
public String getName()
{
return name;
}
class ChildProfileComparator implements Comparator<Main> {
@Override
public int compare(Main o1, Main o2) {
String firstName = o1.getName();
String secondName = o2.getName();
if (firstName == null) {
return +1;
}
if (secondName == null) {
return -1;
}
if(isNumber(firstName) && isNumber(secondName))
{
double d1 = Double.parseDouble(firstName);
double d2 = Double.parseDouble(secondName);
return (d1>d2)?+1:-1;
}
if(isNumber(firstName))
{
return +1;
}
if(isNumber(secondName))
{
return -1;
}
return o1.getName().compareTo(o2.getName());
}
public boolean isNumber(String x)
{
if(x == null)
{
return false;
}
return x.matches("^-?\\d+(\\.\\d+)?$");
}
}
}
Instead of storing each field in its own array list, why not create a class to represent each object such that class will have fields for name, location, position, email, and phone number. When you parse the JSON create an instance of the above mentioned object, and put that into the ArrayList. Make the object Comparable by implementing a comparable interface.. Your compareTo function will simply dereference the name object of the input object and compares to the current object.
See here for more info: http://docs.oracle.com/javase/tutorial/collections/interfaces/order.html
