How to initialize a list with part of an array in Java

Question

In Java, I want to create a list based on part of an array, for example, those starting from position 2 (indexed of course from 0) to position 8, what is the convenient way of doing so without explicitly looping?

Thanks.

because there are faster and better ways?

Yanick Rochon
– Yanick Rochon

2012-01-08 05:52:45 +00:00
Commented Jan 8, 2012 at 5:52 — Yanick Rochon
– Yanick Rochon, Commented Jan 8, 2012 at 5:52
faster? what do you think they run behind the scenes?

Mitch Wheat
– Mitch Wheat

2012-01-08 05:59:25 +00:00
Commented Jan 8, 2012 at 5:59 — Mitch Wheat
– Mitch Wheat, Commented Jan 8, 2012 at 5:59

Eng.Fouad · Accepted Answer · 2013-02-24 10:35:20Z

3

List<String> list = Arrays.asList(Arrays.copyOfRange(array, 2, 8));

EDIT:

To create a variable-size arraylist, use the following:

List<String> list = new ArrayList<String>(Arrays.asList(Arrays.copyOfRange(array, 2, 8)));

edited Feb 24, 2013 at 10:35

answered Jan 8, 2012 at 5:51

Eng.Fouad

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Comments

Borodin · Accepted Answer · 2012-01-08 05:55:31Z

0

Use System.arraycopy

arraycopy(source, 2, destination, 0, 7);

will copy 7 elements from source[2] through source[8] to destination[0] through destination[6].

answered Jan 8, 2012 at 5:55

Borodin

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