PHP - Setting Variables from Inside Functions [duplicate]

Question

Possible Duplicate:
PHP: Global variable scope

How can I set a variable outside a function from inside the function? Here is what I mean:

$myVar = false;

function myFunction($param1 $param2){
    ....
    if($param1 == $x){
        $myVar = $param1;
    }
}

$myVar seems to always stay empty. How can I do this?

Thank you!

fkerber · Accepted Answer · 2012-01-08 20:41:03Z

1

You create a new local variable called `myVar'.

If you would like to stick with your variable outside of the function, you can use the following code to get it working, but global variables are at least in my opinion not the best solution in general.

$myVar = false;

function myFunction($param1 $param2){
    ....
    global $myVar;
    if($param1 == $x){
        $myVar = $param1;
    }
}

answered Jan 8, 2012 at 20:41

fkerber

1,0409 silver badges25 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

user1002039 Over a year ago

Hi, What would be a better solution then?

fkerber Over a year ago

It depends on what you want to achieve and couldn't be answered in this general case. A possible starting point could be to use an additional parameter to get myVar inside your function. Then you can use your exisiting code for the moment but have the possibility to design it better afterwards. For the additional parameter, you need to pass it by reference - see here: php.net/manual/en/language.references.pass.php

Collectives™ on Stack Overflow

PHP - Setting Variables from Inside Functions [duplicate]

1 Answer 1

2 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Linked

Related