1

Edit: I solved it somehow with PHP. Its so specific but I want to share it in case somebody needs it. First of all I didnt give any specific name as product_id for the cookie but I just give the variable of the product_id "$ftc2" which is clicked, shown as below

onclick=\"SetCookie('".$ftc2."', '".$ftc2."', 'expiry'); 

So whenever user clicks on any product, a new cookie is created with the name of the product_id like name=2 or name=32 whatever.

then I have created a foreach on the chart page as below

<?php foreach($_COOKIE as $cookies) { echo $cookies; } ?> 

It displayes now all stored cookie values(in my case product ids) and now I can manipulate it as I want and display all products which is added to chart Maybe it is so easy and so common but somehow I couldnt find it out since morning = )) I hope it saves someone's hours

THE QUESTION WAS:


I am building an onlineshop and What I want to do is displaying all clicked products in showChart page.(a very simple page which shows you the products that you added to your chart by clicking on chart_icon). I have tried some several common methods but I couldnt manage to do it somehow. My last desperate try was creating this addToChart() function.

Since setting the cookie part works good I simplified the code and paste just the important parts (in my opinion). Any kind of help or suggestions would be appreciated. I dont expect anyone to write the code for me.

thanks in advance

    for($i=0;$i<$num;$i++)
        {
            $ftc = mysql_result($result, $i, "product_image");
            $ftc2 = mysql_result($result, $i, "product_id");
            $ftc3 = mysql_result($result, $i, "product_name");
            $ftc4 = mysql_result($result, $i, "product_preis");
            $ftc5 = mysql_result($result, $i, "product_old_preis");
            echo "<a href='details.php?product=".$ftc2."'><div class='products_list'>
            <img width='217px' height='323px' src='".$ftc."'/>
            <div class='alt_yazi2'><b>".$ftc3 ." &nbsp;&nbsp;&nbsp;&nbsp <font      

style='float:right;'>".$ftc4."TL &nbsp;&nbsp<b style='text-decoration:line-through; float:right;'>".$ftc5."TL </b></font></b></a>
    </br>
    <div id='sepet'><a id='cookie' onclick=\"SetCookie('"cookie_product"', '".$ftc2."', 'expiry');\" href='#'>
    <img width='35px' height='25px' src='images/cart_icon.png'/>

JAVASCRIPT CODE BEGINS HERE

var today = new Date(); var expiry = new Date(today.getTime() + 365 * 24 * 60 * 60 * 1000);

    function getCookieVal (offset) {
      var endstr = document.cookie.indexOf (";", offset);
      if (endstr == -1) { endstr = document.cookie.length; }
      return unescape(document.cookie.substring(offset, endstr));
      }

    function GetCookie (name) {
      var arg = name + "=";
      var alen = arg.length;
      var clen = document.cookie.length;
      var i = 0;
      while (i < clen) {
        var j = i + alen;
        if (document.cookie.substring(i, j) == arg) {
          return getCookieVal (j);
          }
        i = document.cookie.indexOf(" ", i) + 1;
        if (i == 0) break;
        }
      return null;
      }

    function SetCookie (name,value,expires,path,domain,secure) {

      document.cookie = name + "=" + escape (value) +
        ((expires) ? "; expires=" + expires : "") +
        ((path) ? "; path=" + path : "") +
        ((domain) ? "; domain=" + domain : "") +
        ((secure) ? "; secure" : "");

      }

    document.getElementById(cookie).onclick = function addToChart()
            {
                var cookieValue = document.getElementById(cookie).value;
                var cookiearray = new Array();
                cookiearray = cookieValue.split(",");
                return cookiearray;

            }
4
  • Post the actual page source (after it's been generated as seen by View/Source in the borwser), not some templating language that most people who can help you here don't know. Commented Jan 10, 2012 at 1:43
  • I solved it somehow Ok I have solved my problem with PHP. Its so specific but I want to share it in case somebody needs it. First of all I didnt give any specific name as product_id for the cookie but I just give the variable of the product_id "$ftc2" which is clicked, shown as below onclick=\"SetCookie('".$ftc2."', '".$ftc2."', 'expiry'); So whenever user clicks on any product, a new cookie is created with the name of the product_id like name=2 or name=32 whatever. Commented Jan 10, 2012 at 1:59
  • then I have created a foreach on the chart page as below <?php foreach($_COOKIE as $cookies) { echo $cookies; } ?> It displayes now all stored cookie values(in my case product ids) and now I can manipulate it as I want and display all products which is added to chart Maybe it is so easy and so common but somehow I couldnt find it out since morning = )) I hope it saves someone's hours Commented Jan 10, 2012 at 1:59
  • You can and should post your solution as an answer to this question(which you can accept later). Commented Jan 10, 2012 at 10:47

1 Answer 1

1

Ok I have solved my problem with PHP. Its so specific but I want to share it in case somebody needs it.

First of all I didnt give any specific name as product_id for the cookie but I just give the variable of the product_id "$ftc2" which is clicked, shown as below

onclick=\"SetCookie('".$ftc2."', '".$ftc2."', 'expiry');

So whenever user clicks on any product, a new cookie is created with the name of the product_id like name=2 or name=32 whatever.

then I have created a foreach on the chart page as below

<?php 
foreach($_COOKIE as $cookies)
     {
             echo $cookies;
      }

?>

It displayes now all stored cookie values(in my case product ids) and now I can manipulate it as I want and display all products which is added to chart

Maybe it is so easy and so common but somehow I couldnt find it out since morning = ))

Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.