How to throw an array exception in php

Question

So I have an error message that gets thrown in one file

$error_message = "Error received for " . $service . ": " . $_r['status'] . "\n" . "Message received: " . $_r['errors'];
throw new My_Exception($error_message);

and in another file I have

try {
    //blah blah
} catch( My_Exception $e ) { 
    var_export($e->getMessage());
}

The problem, however, is that $_r['errors'] is an ARRAY and it get $e->getMessage() just prints it as "Array". How can I modify this code to access the array?

radmen · Accepted Answer · 2012-01-11 18:55:08Z

17

The problem is that You're trying to merge array with a string. It'll always end like this.

Maybe You should pass to exception an array, so You can later make use of it?

<?php
class myException extends Exception {

    private $params;

    public function setParams(array $params) {
        $this->params = $params;
    }

    public function getParams() {
        return $this->params;
    }
}

// later it can be used like this:
try {
    $exception = new myException('Error!');
    $exception->setParams(array('status' => 1, 'errors' => array());

    throw $exception;
}
catch (myException $e) {
    // ...
}
?>

edited Jan 11, 2012 at 18:55

answered Jan 11, 2012 at 18:46

radmen

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2 Comments

Xeoncross Over a year ago

This is bad form as it breaks the basic interface of exceptions. If you need to pass some values - just add a method that collects and stores them.

Xeoncross Over a year ago

+1 Perfect. Now that object is gaining, rather than losing, functionality.

hakre · Accepted Answer · 2012-01-11 18:37:19Z

10

To convert a complex data-structure like an array into a string (e.g. for error messages), you can make use of print_r^Docs and setting it's second parameter to TRUE:

... ": " . print_r($_r['status'], TRUE) . "\n" ...

answered Jan 11, 2012 at 18:37

hakre

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Comments

NerdPanda · Accepted Answer · 2020-08-25 09:21:59Z

2

we can using json format

   throw new Exception(json_encode(['type'=>'error','isExit'=>'true','title'=>'SystemConfigError']));

and in the catch

        catch (Exception $error)
    {
        var_dump(json_decode($error->getMessage(),JSON_OBJECT_AS_ARRAY));
    }

answered Aug 25, 2020 at 9:21

NerdPanda

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Comments

Francis Yaconiello · Accepted Answer · 2012-01-11 18:51:39Z

so your example code is kinda bad, but assuming

$_r['errors'] = array(
    'Message 1',
    'Message 2',
    'Message 3',
    'Message 4',
    'Message 5',
);

Then

$error_message = "Error received for " . $service . ": \n" . impolode("\n", $_r['errors']) . "\n" . "Message received: " . $_r['errors'];
throw new My_Exception($error_message);

The key is taking your array of error messages and concatenating them all together with newlines (or whatever)

But I kinda agree with the comment that you may be using the Exception framework wrong. Can you post what you are trying to do?

The general rule of thumb is that you throw an exception for each unique event. You dont collect a bunch of error messages and then throw them all at once.

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