php error: Call to a member function fromArray() on a non-object

Question

I am trying to set up a "forgot password" system. User enters email and if it exists a new email is recorded and sent to the user email address entered. The user email check works ok. When trying to enter a new passord into system it does not.

The code is this:

..... (form is_valid and check email ok)

if(is_object($object)) {

        $newpassword = substr(str_shuffle(str_repeat('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789',8)),0,8);

        $input = $form->getValues();

        $user = Doctrine::getTable('Tcc_Model_User')
            ->find($input['email']);

        $user->fromArray($input);
        $user->Password = md5($newpassword);
        $user->save();
......
email send

} else {
    $form->getElement('email')->addError('Sorry, there is no record of that email adddress.');
  }

the error I get is this:

Call to a member function fromArray() on a non-object

Could someone help me figure out what I am doing wrong? Please.

Jon · Accepted Answer · 2012-01-12 15:27:50Z

6

Simply put, $user is not an object. It's probably either false or null, signifying that find() did not actually find what it was looking for.

You can see what $user actually is with var_dump($user), and then you should read the documentation for find to see why it's returning that.

answered Jan 12, 2012 at 15:27

Jon

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11 Comments

Iznogood Over a year ago

Or the Zend way with: Zend_Debug::dump($user); :)

jbrtrnd Over a year ago

But $user id the result of Doctrine::getTable('Tcc_Model_User')->find($input['email']); so it's maybe a row (Zend Framework) and not an object of user's class.

Jon Over a year ago

@JBRTRND-DEV: There is no object of class user involved here. The intent of the code is clear: find the row with the specified email, update its other fields based on input, and save it. There's no user object logically involved in this.

jbrtrnd Over a year ago

@Jon : I agree, here there's no class or object "user" but what I tried to explain, is that $user is already affected (row, array, boolean, null) by ->find() function, and in this way, $user->fromArray doesn't work.

Jon Over a year ago

@JBRTRND-DEV: $user is the result of the find function, it's not affected by it.

|

DaveRandom · Accepted Answer · 2012-01-12 15:32:56Z

0

According to the docs, Doctrine_Table::find() (called on the line above your error) returns one of the following entities:

Doctrine_Collection, array, Doctrine_Record or false if no result

This means that you need to check what was returned before you try and use the value, $user, as if it were an object exposing the fromArray() method.

answered Jan 12, 2012 at 15:32

DaveRandom

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3 Comments

firefiter Over a year ago

Isn't if(is_oject($object) telling me that is returning a value?

DaveRandom Over a year ago

You also need if (is_object($user)), since it is the $user variable that is triggering the error.

firefiter Over a year ago

So as @JBRTRND-DEV says if find() only works on primary key that could be the problem. Also because the very same code works ok in other situations

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