This works:
print "Hello World%s" %"!"
But this doesn't
print "Hello%20World%s" %"!"
the error is ValueError: unsupported format character 'W' (0x57) at index 8
I am using Python 2.7.
Why would I do this? Well %20 is used in place of spaces in urls, and if use it, I can't form strings with the printf formats. But why does Python do this?
You could escape the % in %20 like so:
print "Hello%%20World%s" %"!"
or you could try using the string formatting routines instead, like:
print "Hello%20World{0}".format("!")
You could escape the % with another % so %%20
This is a similar relevant question Python string formatting when string contains "%s" without escaping
I was using python interpolation and forgot the ending s character:
a = dict(foo='bar')
print("What comes after foo? %(foo)" % a) # Should be %(foo)s
Watch those typos.
You might have a typo.. In my case I was saying %w where I meant to say %s.
Well, why do you have %20 url-quoting escapes in a formatting string in first place? Ideally you'd do the interpolation formatting first:
formatting_template = 'Hello World%s'
text = '!'
full_string = formatting_template % text
Then you url quote it afterwards:
result = urllib.quote(full_string)
That is better because it would quote all url-quotable things in your string, including stuff that is in the text part.
For anyone checking this using python 3:
If you want to print the following output "100% correct":
python 3.8: print("100% correct")
python 3.7 and less: print("100%% correct")
A neat programming workaround for compatibility across diff versions of python is shown below:
Note: If you have to use this, you're probably experiencing many other errors... I'd encourage you to upgrade / downgrade python in relevant machines so that they are all compatible.
DevOps is a notable exception to the above -- implementing the following code would indeed be appropriate for specific DevOps / Debugging scenarios.
import sys
if version_info.major==3:
if version_info.minor>=8:
my_string = "100% correct"
else:
my_string = "100%% correct"
# Finally
print(my_string)
