What is the best way to get outputted list and variables nicely into an HTML template?
list = ['a', 'b', 'c']
template = '''<html>
<title>Attributes</title>
- a
- b
- c
</html>'''
Is there an easier way to do this?
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3 Answers
You should probably have a look at some template engine. There's a complete list here.
In my opinion, the most popular are:
For example in jinja2:
import jinja2
template= jinja2.Template("""
<html>
<title>Attributes</title>
<ul>
{% for attr in attrs %}
<li>{{attr}}</li>
{% endfor %}
</ul>
</html>""")
print template.render({'attrs': ['a', 'b', 'c']})
This will print:
<html>
<title>Attributes</title>
<ul>
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
</html>
Note: This is just a small example, ideally the template should be in a separate file to keep separate business logic and presentation.
Comments
If a template engine is too heavy weight for you, you could do something like
list = ['a', 'b', 'c']
# Insert newlines between every element, with a * prepended
inserted_list = '\n'.join(['* ' + x for x in list])
template = '''<html>
<title>Attributes</title>
%s
</html>''' %(inserted_list)
>>> print template
<html>
<title>Attributes</title>
* a
* b
* c
</html>
2 Comments
I82Much
That being said, I do like template engines and my favorite is StringTemplate - there are python bindings available as well. Stringtemplate.org or you can play around with it at stringtemplate.appspot.com
Paolo
To give OP some more context, this is how Python documentation explains the interpolation operator: String Formatting Operations.
HTML doesn't support whitespace, meaning:
'\n'.join(x for x in list) #won't work
You'll want to try the following.
'<br>'.join(x for x in list)
Otherwise templates is the way to go!
