How to convert JavaScript to CoffeeScript for two case

Question

I'm using CoffeeScript in a Rails application. How to convert JavaScript to CoffeeScript for two case:

var colIndex = 0,
    colRight = 0,
    cols = this.grid.columnX,
    len = cols.length,
    cmatch = false;

for (len; colIndex < len; colIndex++) {
    colRight = cols[colIndex].x + cols[colIndex].w;
    if (xy[0] < colRight) {
        cmatch = true;
    break;
    }
}

and

setTimeout(function() {
    d.scrollTop = st;
}, 10);

Thank you in advance for your help!

possible duplicate of Is there a tool for converting JavaScript to CoffeeScript? — Jan Hančič
– Jan Hančič, Commented Jan 17, 2012 at 10:46

qiao · Accepted Answer · 2012-01-17 10:48:59Z

1

1.CoffeeScript supports for in iteration on an array, so you simply don't need colIndex and len.

colRight = 0
cols = @grid.columnX
cmatch = false

for col in cols
  colRight = col.x + col.w
  if xy[0] < colRight
    cmatch = true
    break

2.

setTimeout (-> d.scrollTop = st), 10

answered Jan 17, 2012 at 10:48

qiao

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1 Comment

Chris Subagio Over a year ago

The setTimeout looks fine, but you'd overlooking that the OP might have actually wanted to have the index of the matching item. See my answer for a solution that provides that.

island205 · Accepted Answer · 2012-01-18 05:42:54Z

0

there is a site to do this work js2coffee:

the answers are:

1

colIndex = 0
colRight = 0
cols = @grid.columnX
len = cols.length
cmatch = false
len
while colIndex < len
  colRight = cols[colIndex].x + cols[colIndex].w
  if xy[0] < colRight
    cmatch = true
    break
  colIndex++

2

setTimeout (->
  d.scrollTop = st
), 10

answered Jan 18, 2012 at 5:42

island205

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Comments

Chris Subagio · Accepted Answer · 2012-01-18 20:22:38Z

0

Here's my stab at it:

for col, idx in @grid.columnX when xy[0] < colRight = (col.x + col.w)
  cmatch = idx
  break

So after the loop, cmatch will either be undefined or the index of the match, while colRight will be the matching col's right side, or the last col's right side if no match is found.

Here's a fiddle to play in: http://jsfiddle.net/fNSXE/1/

answered Jan 18, 2012 at 20:22

Chris Subagio

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