how to print values for an array in xcode?

Question

I have a text box in my XIB named "txt" and a button named "next". Now on the click of next button I want to print values of myArray.

NSArray *myArray
 myArray = [NSArray arrayWithObjects:@"1",@"3",@"5",@"45",@"67",nil];

can anyone help me with this.

u want to print in the console? or in the testfield...

Shanti K
– Shanti K

2012-01-20 06:29:54 +00:00
Commented Jan 20, 2012 at 6:29 — Shanti K
– Shanti K, Commented Jan 20, 2012 at 6:29

X Slash · Accepted Answer · 2012-01-20 06:30:05Z

13

This will do

NSLog(@"%@", myArray);

answered Jan 20, 2012 at 6:30

X Slash

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Comments

Sanjeev Rao · Accepted Answer · 2012-01-20 06:37:38Z

4

NSArray *myArray  = [NSArray arrayWithObjects:@"1",@"3",@"5",@"45",@"67",nil];
-(IBAction)nextAction:(id)sender{

NSString *currentObj = txt.text;
int index = -1;

if(currentObj != nil&&[myArray containsObject:currentObj]){
index = [myArray indexOfObject:currentObj];
} 

index++;
if(index<myArray.count)
   txt.text = [myArray objectAtIndex:index];

}

answered Jan 20, 2012 at 6:37

Sanjeev Rao

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Comments

Yama · Accepted Answer · 2012-01-20 06:31:07Z

0

button.title = [myArray objectatindex:index];

answered Jan 20, 2012 at 6:31

Yama

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Comments

Shubhank · Accepted Answer · 2012-01-20 06:31:51Z

0

NSArray *myArray myArray = [NSArray arrayWithObjects:@"1",@"3",@"5",@"45",@"67",nil];

change it to

NSArray *myArray = [NSArray arrayWithObjects:@"1",@"3",@"5",@"45",@"67",nil];

Otherwise you are doomed: D

answered Jan 20, 2012 at 6:31

Shubhank

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2 Comments

Yama Over a year ago

this is not the solution to the question,write this in comment and also I guess that would be by mistake.

Shubhank Over a year ago

ok..ok...just saying..i was also thinking how doesn't the program already show any error..NSLog will suffice as a solution

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