Call JSP method (or PHP script) from Javascript?

Question

Is it possible to call one of my JSP methods from a Javascript Onclick event?

I don't want my user to leave the current page. I need the javascript to call the method, which then runs the SQL update to increment in the database. I read somewhere I could use a hidden Iframe to accomplish this as well...

en.wikipedia.org/wiki/Ajax_(programming)

Phil
– Phil

2012-01-24 23:53:48 +00:00
Commented Jan 24, 2012 at 23:53 — Phil
– Phil, Commented Jan 24, 2012 at 23:53

SeanCannon · Accepted Answer · 2012-01-24 23:56:29Z

1

$('myElement').click(function(){
    $.ajax({
        url: '/path/to/php/file.php?method=foo',
        success: function(data){
            // do something with data, which is the output of your php file
        }
    });
});

answered Jan 24, 2012 at 23:56

SeanCannon

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3 Comments

Phil Over a year ago

Your selector needs looking at

Luca DeCaprio Over a year ago

I'm not really sure how to apply this... here is my js code: function feedVote(postId, vote){ if(vote == "1") { document.getElementById('voteUpSpan' + postId).innerHTML = "Thank you for voting!"; document.getElementById('voteDownSpan' + postId).innerHTML = ""; } else{ document.getElementById('voteDownSpan' + postId).innerHTML = "Thank you for voting!"; document.getElementById('voteUpSpan' + postId).innerHTML = ""; } }

Luca DeCaprio Over a year ago

And this is what it is referring too: <a href='#' id='voteUp" + results.getString("id") + "' onclick='feedVote(" + results.getString("id") + ", 1)';>

Ali Muzaffar Khan · Accepted Answer · 2012-01-24 23:58:22Z

1

Yes you can use hidden iFrame to do this but in my opinion would be to use AJAX. If you'r using jQuery it is pretty straight forward. Just invoke an ajax request on click.

No idea how to do AJAX using jQuery? I am also pasting the links. Pretty straight forward.

http://api.jquery.com/jQuery.post/

http://api.jquery.com/jQuery.get/

http://api.jquery.com/jQuery.ajax/

answered Jan 24, 2012 at 23:58

Ali Muzaffar Khan

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Comments

u.k · Accepted Answer · 2012-01-24 23:58:10Z

0

Your options are:

answered Jan 24, 2012 at 23:58

u.k

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