How to multiplying, multiple inputs from using while loop in c

Question

I have to multiply digits by taking input from the user and when he enter 'n' it will produce the answer.

For example (2*3*2 = 12). But I manage to write the code for taking two inputs but can't find the way to take multiple inputs from user and produce the total answer. Here is the code;

void main (void)
            {
                float f1,f2;
                float total;
                int status1,status2;
                printf("Enter first number to multiply:'n' to quit.\n ");
                status1=scanf("%f",&f1);
                printf("Enter another number to be multiply:'n' to quit.\n ");
                status2=scanf("%f",&f2);
                while (status1==1 && status2==1)
                    {
                        total=f1*f2;
                        status1=scanf("%1.0f",&f1);
                        status2=scanf("%1.0f",&f2);
                    }
                printf("Multiplition Total = %1.0f",total);
                getch();
            }

@Macmade No, seriously I am new in programming and I am learning C. — AbdulAziz
– AbdulAziz, Commented Jan 25, 2012 at 11:52

MetallicPriest · Accepted Answer · 2012-01-25 12:12:47Z

1

You can use a while loop, as follows.

 float prod = 1, f;

 printf( "Enter the numbers, n to stop.\n" );
 while( scanf( "%f", &f ) )
   prod *= f;
 printf( "product = %f\n", prod );

edited Jan 25, 2012 at 12:12

answered Jan 25, 2012 at 11:53

MetallicPriest

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2 Comments

AbdulAziz Over a year ago

Thank you for the answer, but can i use without bounding the user for put input not more than 100, I mean can I do it without max input limits.

MetallicPriest Over a year ago

Yes you may calculate the product on the fly, like shown in the edited code.

Adam Stelmaszczyk · Accepted Answer · 2012-01-25 12:43:58Z

Tested:

#include <stdio.h>

int main()
{
    int total = 1, factor = 1, success;
    do
    {
        total *= factor;
        printf("Enter integer number to multiply or 'n' to quit: ");
        success = scanf("%d", &factor);
    }
    while (success);
    printf("Multiplication Total = %d\n", total);
    return 0;
}

And a piece of advice as you said you start your adventure with C:
Unless you have some specific reason to do otherwise, use double, not float.
However, in your question you asked for digits (integer) multiplication, so int is sufficient. If you can avoid floating point numbers, avoid them. They're much more complicated then integers and can let you in worse problems if you don't use them with caution.
You can refer to What Every Computer Scientist Should Know About Floating-Point Arithmetic.

hmjd · Accepted Answer · 2012-01-25 13:56:10Z

0

This would do what you need and handles, 0, 1 or an unlimited number of inputs:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    float f1;
    float total = 0;

    printf("Enter number: ");
    if (scanf("%f",&total))
    {
        for (;;)
        {
            printf("Enter number: ");
            if (!scanf("%f", &f1))
            {
                break;
            }
            total *= f1;
        }
    }

    printf("Multiplication Total = %f\n",total);

    getch();

    return 0;
}

It keeps a running total as values are entered but it stops on first invalid input, not just when n is entered.

edited Jan 25, 2012 at 13:56

answered Jan 25, 2012 at 12:13

hmjd

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4 Comments

AbdulAziz Over a year ago

Thanks a lot, it worked. But I have a question that can I by any mean write the statement of if with the statement of while. (by using && or || operators).

hmjd Over a year ago

I have edited the code to add the write of the question. Note, this answer has recieved a downvote so there may be a mistake (I don't what mistake I have made and downvoter has not provided a reason for the downvote).

hmjd Over a year ago

BTW, if you just need to process integers change float to int and scanf()/printf() format specifier to %d.

ams Over a year ago

That's exactly the same solution as mine, but coded a little less efficiently (and without the fflush calls which should be needed, but apparently aren't on Turbo C).

ams · Accepted Answer · 2012-01-25 12:03:34Z

0

Untested:

float f, p = 1;

printf ("Enter a number: ");
fflush (stdout);
while (scanf("%f", &f) != EOF)
  {
    p *= f;
    printf ("Enter another number: ");
    fflush (stdout);
  }

printf ("Product: %f\n", p);

answered Jan 25, 2012 at 12:03

ams

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6 Comments

AbdulAziz Over a year ago

Just for your info. Iam using Turbo C 3.0 compiler. Thank you

ams Over a year ago

The above is (a fragment of) standard C. If your compiler can't cope with that then it's not a C compiler. ;) You'll need to wrap it in a function, of course.

AbdulAziz Over a year ago

Sorry not worked the code for me, as my compiler does not support fflush() functtion...any other solution?

Gandaro Over a year ago

@AbdulAziz Yes, there is another solution... Install a real C compiler. ;)

AbdulAziz Over a year ago

@Gandaro Thanks for the kind advice. But can you advice me compiler better that Turbo C 3.0 compiler. I mean simpler and efficient that this one. please

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