I need your help with a RegEx in PHP
I have something like: vacation.jpg and I am looking for a RegEx which extracts me only the 'vacation' of the filename. Can someone help me?
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possible duplicate of PHP Get File Name Without File ExtensionQtax– Qtax2012-01-27 13:20:56 +00:00Commented Jan 27, 2012 at 13:20
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You do not need regular expression for this - PHP has built-in features that enable you to do this without regular expressions.Tadeck– Tadeck2012-01-27 13:22:12 +00:00Commented Jan 27, 2012 at 13:22
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5 Answers
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You can use pathinfo instead of Regex.
$file = 'vacation.jpg';
$path_parts = pathinfo($file);
$filename = $path_parts['filename'];
echo $filename;
Comments
And if you really need regex, this one will do it:
$success = preg_match('~([\w\d-_]+)\.[\w\d]{1,4}~i', $original_string, $matches);
Inside matches you will have first part of file name.
Comments
Better answers have already been provided, but here's another alternative!
$fileName = "myfile.jpg";
$name = str_replace(substr($fileName, strpos($fileName,".")), "", $fileName);
Comments
You don't need regex for this.
Approach 1:
$str = 'vacation.jpg';
$parts = explode('.', basename($str));
if (count($parts) > 1) array_pop($parts);
$filename = implode('.', $parts);
Approach 2 (better, use pathinfo()):
$str = 'vacation.jpg';
$filename = pathinfo($str, PATHINFO_FILENAME);
