Parse string in javascript

Question

How can I parse this string on a javascript,

var string = "http://www.facebook.com/photo.php?fbid=322916384419110&set=a.265956512115091.68575.100001022542275&type=1";

I just want to get the "265956512115091" on the string. I somehow parse this string but, still not enough to get what I wanted.

my code:

var newstring = string.match(/set=[^ ]+/)[0];

returns:

a.265956512115091.68575.100001022542275&type=1

To properly parse this, you should first dissect it into its parts (e,g, the key-values of the query string), then URL-decode the key and value, and only then extract the data you're interested in from the value with the key you're interested in. — Lucero
– Lucero, Commented Jan 28, 2012 at 13:40

Royi Namir · Accepted Answer · 2012-01-28 13:35:46Z

5

try this : 

  var g=string.match(/set=[a-z]\.([^.]+)/);

g[1] will have the value

http://jsbin.com/anuhog/edit#source

edited Jan 28, 2012 at 13:35

answered Jan 28, 2012 at 13:29

Royi Namir

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Community · Accepted Answer · 2017-05-23 12:06:35Z

3

You could use split() to modify your code like this:

var newstring = string.match(/set=[^ ]+/)[0].split(".")[1];

For a more generic approach to parsing query strings see:

Parse query string in JavaScript

Using the example illustrated there, you would do the following:

var newstring = getQueryVariable("set").split(".")[1];

edited May 23, 2017 at 12:06

CommunityBot

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answered Jan 28, 2012 at 13:27

biscuit314

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2 Comments

biscuit314 Over a year ago

My first instinct was to modify the regex too, but I thought the more general notion of parsing a query string was helpful. Braveyard's answer answer (linked above) is based on split() and I just carried forward in kind.

Lucero Over a year ago

If you want something generic, then by all means do apply proper URL decoding!

Ian · Accepted Answer · 2022-01-26 06:30:57Z

0

You can use capturing group in the regex.

const str = 'http://www.facebook.com/photo.php?fbid=322916384419110&set=a.265956512115091.68575.100001022542275&type=1';

console.log(/&set=(.*)&/.exec(str)[1]);

answered Jan 26, 2022 at 6:30

Ian

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