I have a php array with 4 entries. And I need to call a class method using the data in my array.
$array = array('USER', 'username', 'other', 'test');
This I want to use to generate this
$array[0]::find_by_$array[1]($array[3]);
it must look as
USER::find_by_username(test);
How I can convert the array values into this line?
What is the correct syntax?
call_user_func_array(array($array[0],'find_by_'.$array[1]),$array[3])
But this isn't the cleanest way to manage your code, there's no validation that the class or method exists, so subject to potential failure
You can use call_user_func_array to call a callback with an array as parameters:
$callback = array($array[0], 'find_by_'.$array[1]);
$params = array($array[3]);
$ret = call_user_func_array($callback, $params);
call_user_func_array(array($array[0], 'find_by_'.$array[1]), $array[3]);
You were very close to what is valid syntax as of PHP5.4. You merely need to use curly braces and quoting to encapsulate the method name. Demo
Set up:
class USER // should be a StudlyCased class name
{
static function find_by_username($name)
{
printf('You tried to find a user by username "%s"', $name);
}
}
$array = array('USER', 'username', 'other', 'test');
Valid modern calls without call_user_func_array():
Interpolation:
$array[0]::{"find_by_{$array[1]}"}($array[3]);
Concatenation:
$array[0]::{'find_by_' . $array[1]}($array[3]);
Output: You tried to find a user by username "test"
@Gumbo's correct implementation will work all the way down to PHP5.0. Demo
call_user_func_array(
array($array[0], 'find_by_' . $array[1]),
array($array[3])
);