Concatenate 2 variables (Powershell)

Question

I have got a list of 20 servers : server1, server2, server3, server4, ... server20.

I need to have an array "servers" that contains these 20 servers, something like :

$prefix = "server"
$number = "1..20"
$servers = $prefix+number

My expected output : $servers="server1","server2","server3",...,"server20"

Thanks in advance

Joey · Accepted Answer · 2012-02-01 17:53:20Z

3

The easiest way is to just spell it out directly:

$servers = 1..20 | ForEach-Object { "server$_" }

answered Feb 1, 2012 at 17:53

Joey

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JNK · Accepted Answer · 2012-02-01 14:31:46Z

1

Change your last line to:

$Servers = @()
$Number | % {$servers=$servers + "$prefix$_"}

The first line specifies $servers as an array (otherwise it would be concatenated as a long string).

The second line will go through all the digits in your $number array and make an entry for each one.

edited Feb 1, 2012 at 14:31

answered Feb 1, 2012 at 14:26

JNK

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2 Comments

JNK Over a year ago

@Joey - feel free to post an answer. I can get by in PS but I'm not a pro, so if you have a better method I would be excited to see it.

Joey Over a year ago

Maybe I just have peculiar ideas of how idiomatic PowerShell code should look. But I usually find that if you write things how you'd do it in Java or C# it looks really complicated and awkward.

mjolinor · Accepted Answer · 2012-02-01 16:05:11Z

1

Using a format string

$prefix = "Server"
 1..20 | foreach {"$prefix{0}" -f $_}

You can also use $prefix{0:d2} if you want them to all have 2-digit (zero-filled) numbers after the prefix.

edited Feb 1, 2012 at 16:05

answered Feb 1, 2012 at 14:39

mjolinor

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Comments

zx38 · Accepted Answer · 2012-02-05 05:40:16Z

0

$null, $servers = 0..20 -join ';server' -split ';'
$servers

answered Feb 5, 2012 at 5:40

zx38

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2 Comments

Joey Over a year ago

That's quite a bit convoluted. Imho it's almost always better to make your intent clear – that's not what I see here.

zx38 Over a year ago

@Joey Just showing other ways. Simplest way is to use the replace operator: 1..20 -replace '^', 'server'

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