PHP - Overloaded class function

Question

Helo everyone.

I have a class MyClass and a function escape() that can be called as a static class or as an instantiated Object.

MyClass::_escape('..... some string...');

or

$myclass->escape();

What I would like is not to have the underscore on the staic version and for both just have the same function definition. I trie to do.

    class MyClass {

    public $_string = "";

      public function escape($string = null) {

            if($string == null) 
                  return new String(mysql_real_escape_string($this->_string));
            else
                  return new String(mysql_real_escape_string($string)); 

      }


   }

but this function fails by the PHP parser. Is there a way of doing what I attempted to above??

So to summarise, I would like the static call to look like;

   print Myclass::escape('some string');

and the instantiated call to look like;

   print $myobject->escape(); //Which escapes the private variable _string

Hope this was clear.

regards

Thanks everyone for your suggestions .. comments. I learn a little more every day. :) — IEnumerable
– IEnumerable, Commented Feb 2, 2012 at 15:52

dynamic · Accepted Answer · 2012-02-02 15:33:16Z

3

public function _escape($s){
  return self::escape($s);
}

answered Feb 2, 2012 at 15:33

dynamic

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3 Comments

IEnumerable Over a year ago

So you suggest having both functions but the instatiated object calls the static function. If so, thats what I currently have, just would be nice to have the same function name. ..regards

dynamic Over a year ago

this is your best bet considering your broken design

IEnumerable Over a year ago

ok, so is having the same name NOT possible? Ive been coding in PHP 5 for 2 months now and just trying to understand the restrictions

Yoshi · Accepted Answer · 2012-02-03 15:41:18Z

2

What you're trying to achieve won't work without at least some kind of error:

Example using static:

error_reporting(E_ALL ^ E_STRICT);

class MyClass
{
  // note the *static* keyword
  public static function escape($string = null) {
    // $this is not defined, even if called as object-method 
    var_dump(isset($this));
  }
}

$foo = new MyClass();
$foo->escape(); // => bool(false)

MyClass::escape(); // => bool(false)

So, if you remove the static keyword and try again, you'll get:

$foo->escape(); // => bool(true)

but also:

Strict Standards: Non-static method MyClass::escape() should
not be called statically ...

for

MyClass::escape(); // => bool(false)

edited Feb 3, 2012 at 15:41

answered Feb 2, 2012 at 15:45

Yoshi

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Comments

Community · Accepted Answer · 2017-05-23 12:03:32Z

1

There are no parse errors in the code you posted. In fact, it works just as you want it to work, as long as you never pass $string to the escape() method in an object context:

$foo = new MyClass();
$foo->_string = 'foo';
$foo->escape(); // This works.
MyClass::escape('bar'); // This works, too.
$foo->escape('baz'); // Don't do this.  It'll escape $string instead of $this->_string.

You could resolve this issue by determining whether or not you're in a static context within the escape() method, instead of checking for the existence of $string.

edited May 23, 2017 at 12:03

CommunityBot

11 silver badge

answered Feb 2, 2012 at 15:49

FtDRbwLXw6

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