int[][] myArray = new int[10][];
foreach (int[] eachArray in myArray) {
eachArray = new int[2]
}
I believe it should create an array that is
{ 0 , 0 }
{0 , 0}
.........
Jagged array is so confusing.....
2 Answers
This will not create the jagged array you are looking for. It's attempting to assign a new int[2] instance to the iteration variable, not to the slot in the original array. This won't even compile as the iteration variable is treated as readonly by the compiler
The way to do this is with a for loop
for (var i = 0; i < myArray.Length; i++) {
myArray[i] = new int[2];
}
3 Comments
Bug
Thank you, however should I always use that approach? It seemed using for loop is quite ugly to me... Is there any prettier way to do it?
JaredPar
@user1143720 the
for loop is the standard way of doing it. It can be done with a full blown initializer but that requires initializing the entire array inline.Bug
sorry for this dumb question. I will do more research before I post next question.
Assigning to loop variables inside foreach loop is not allowed. You need a regular for loop with a counter, or you can try something slightly fancier:
int[][] myArray = Enumerable.Range(0, 10).Select(i => new int[2]).ToArray();
answered Feb 2, 2012 at 22:44
Sergey Kalinichenko
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List<List<int>>instead. It has also the advantage that it's resizable without overhead(copying into another array).