using awk within loop to replace field

Question

I have written a script finding the hash value from a dictionary and outputting it in the form "word:md5sum" for each word. I then have a file of names which I would like to use to place each name followed by every hash value i.e. tom:word1hash tom:word2hash . . bob:word1hash

and so on. Everything works fine but I can not figure out the substitution. Here is my script.

$#!/bin/bash
#/etc/dictionaries-common/words
cat words.txt | while read line; do echo -n "$line:" >> dbHashFile.txt  
echo "$line" | md5sum | sed 's/[ ]-//g' >> dbHashFile.txt; done
cat users.txt | while read name
do
cat dbHashFile.txt >> nameHash.txt;
awk '{$1="$name"}' nameHash.txt;
cat nameHash.txt >> dbHash.txt;
done

the line

    $awk '{$1="$name"}' nameHash.txt;

is where I attempt to do the substitution.

thank you for your help

Arkku · Accepted Answer · 2012-02-06 04:27:51Z

2

Try replacing the entire contents of the last loop (both cats and the awk) with:

awk -v name="$name" -F ':' '{ print name ":" $2 }' dbHashFile.txt >>dbHash.txt

answered Feb 6, 2012 at 4:27

Arkku

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2 Comments

slev Over a year ago

Thank you. It works perfect. I wish I could +1 you. So you must redeclare variables when used in an awk expression?

Arkku Over a year ago

Awk won't take variables from the environment, no. Of course you could also do awk -F : { print "'"$name"'" ":" $2 }' instead. (As for +1, I believe you can still accept the answer by clicking the checkmark thingy, which you should do if it worked for you. =)

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