How to parse this JSON string

Question

I'm trying to parse this string into java, but I keep getting errors.

{"id":1,"jsonrpc":"2.0","result":{"limits":{"end":3,"start":0,"total":3},"sources":[{"file":"/media/storage/media/re Music/","label":"re Music"},{"file":"/media/storage/media/ra Music/","label":"ra Music"},{"file":"addons://sources/audio/","label":"Music Add-ons"}]}}

When I use this code ...

String temp = //json code returned from up above
JSONObject obj = new JSONObject(temp);
JSONArray array = obj.getJSONArray("sources");

I get an error saying org.json.JSONObject Value... and then displays what is in temp. Any help?

Gus · Accepted Answer · 2012-02-10 22:45:09Z

2

The array named "sources" is several levels deep. You need to traverse down into the json.

Code formatters help with this stuff...

http://jsonformatter.curiousconcept.com/

{
   "id":1,
   "jsonrpc":"2.0",
   "result":{
      "limits":{
         "end":3,
         "start":0,
         "total":3
      },
      "sources":[
         {
            "file":"/media/storage/media/re Music/",
            "label":"re Music"
         },
         {
            "file":"/media/storage/media/ra Music/",
            "label":"ra Music"
         },
         {
            "file":"addons://sources/audio/",
            "label":"Music Add-ons"
         }
      ]
   }
}

answered Feb 10, 2012 at 22:45

Gus

6,9056 gold badges39 silver badges60 bronze badges

Sign up to request clarification or add additional context in comments.

8 Comments

Andrew Butler Over a year ago

ok that makes more sense, but how would go into a nested statement like this? like this? JSONArray ar = obj.getaray("results")

Miserable Variable Over a year ago

@user987103 what is getarray? What is "results"?

Gus Over a year ago

I don't know the details of the exact library you are using, (you haven't actully told us though I probably could figure it out from the package name). Typically, you would do obj.get("result").getArray("sources"). Check your javadoc for the exact specifics on method namees

Andrew Butler Over a year ago

oh I'm just using org.json .. is there an easier one to use?

Gus Over a year ago

There are lots out there, but there are lots of stack overflow questions adressing the pros and cons. Which line gives you the error, the second or the third (in your original code)

|

CaseyB · Accepted Answer · 2012-02-10 22:45:00Z

0

It looks like the "sources" array is in the "result" object. So you would need to get that object and then get the array from that like this:

JSONObject obj = new JSONObject(temp);
JSONObject result = obj.getJSONObject("result");
JSONArray array = result.getJSONArray("sources");

answered Feb 10, 2012 at 22:45

CaseyB

25.1k16 gold badges81 silver badges115 bronze badges

1 Comment

Andrew Butler Over a year ago

everytime I put the result string into a JSONObject it throws that same exception

kosa · Accepted Answer · 2012-02-10 22:47:46Z

0

Your json should have top level object, from there you need to get child objects. See this link for more detail.

answered Feb 10, 2012 at 22:47

kosa

66.7k15 gold badges134 silver badges170 bronze badges

1 Comment

Andrew Butler Over a year ago

that's the thing though, once I put that temp string into a JSONObject it throws an error. I know that I have to go into a nested result, but it just throws that error.

Collectives™ on Stack Overflow

How to parse this JSON string

3 Answers 3

8 Comments

1 Comment

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

8 Comments

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related