PowerShell: Output of Regular Expression instead of Result

Question

Ok, long time visitor, first time post.

Instead of PowerShell telling me the result of my Regular Expression is "True" or "False", instead I would like the string. I know there are other ways to do this and I already have a working version, but I would like to use Regular Expressions to "extract" the string.

For example:

$ipconfig = ipconfig | select-string "IPv4" | select-object -first 1
$ipconfig -match "\b\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\b"

Just returns "True", instead I would like the IP address.

Is there a way of accomplishing this using regex?

Thanks!

Daniel Richnak · Accepted Answer · 2012-02-13 22:36:10Z

9

You've already got it, just need to check a variable you get for free:

$ipconfig = ipconfig | select-string "IPv4" | select-object -first 1
if ($ipconfig -match "\b\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\b") { 
    $matches[0]
}

Alternatively, you can use the .NET object:

$ipconfig = ipconfig | select-string "IPv4" | select-object -first 1
([regex]"\b\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\b").matches($ipconfig) | % { $_.value }

Enjoy :)

answered Feb 13, 2012 at 22:36

Daniel Richnak

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mjolinor · Accepted Answer · 2012-02-13 22:38:57Z

1

Using -replace:

 $ipconfig = ipconfig | select-string "IPv4" | select-object -first 1 
 $ipconfig -replace '.*\b(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})\b.*','$1'

answered Feb 13, 2012 at 22:38

mjolinor

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