JSONArray with ":" character in Android

Question

 {"1": {
         "StoreName": "イオン八千代緑が丘店",
         "StoreTel": "047-480-3660",
         "StoreAddress": "〒276-0049 千葉県八千代市緑ヶ丘２－１－３　２Ｆ",
         "WorkingTimeInNormalDay": "7:30 AM - 9:00PM",
         "WorkingTimeInWeekend": "9:00-22:00",
         "HaveKidProduct": "N"
     }}

i want to read this json:

JSONObject json ,jChild;
JSONArray jsonNames, jsonValues;
JSONArray jChildNames,jChildValues;
json = new JSONObject(resultString);

jsonNames = json.names();
jsonValues = json.toJSONArray(jsonNames);
for (int i = 0; i < jsonNames.length(); i++) {
jChild = jsonValues.getJSONObject(i);
jChildNames = jChild.names();
jChildValues = jChild.toJSONArray(jChildNames);

Log.i(getCallingPackage(), "No : " + jsonNames.getString(i));
                for (int j = 0; j < jChildNames.length(); j++){
                    Log.i(getCallingPackage(),jChildNames.getString(j) + " : " + jChildValues.getString(j).trim());

                }

}
}

There problems here is: When i parse this:

"WorkingTimeInNormalDay": "7:30 AM - 9:00PM", i have

jChildValues.getString(j) return "7" not "7:30 AM - 9:00PM"

i think may be ":" character is the root cause

How can i solve this problems?

Thanks

===========

Edited:

This is my mistake

Everything working like a champ

No, "7:30 AM - 9:00PM" shouldn't be causing any problem as its enclosed within double quotes — waqaslam
– waqaslam, Commented Feb 14, 2012 at 12:30
but if i dont have "WorkingTimeInNormalDay": "7:30 AM - 9:00PM", "WorkingTimeInWeekend": "9:00-22:00", everything is correct — Nam Vu
– Nam Vu, Commented Feb 14, 2012 at 12:56

Vamshi · Accepted Answer · 2012-02-14 12:41:33Z

1

Before parsing the json try to print the total json string so that you will know that "WorkingTimeInNormalDay": "7:30 AM - 9:00PM" is coming correctly or not. Because if you parse the json the WorkingTimeInNormalDay will give you 7:30 AM - 9:00PM

answered Feb 14, 2012 at 12:41

Vamshi

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2 Comments

Nam Vu Over a year ago

"StoreName": "イオン八千代緑が丘店", "StoreTel": "047-480-3660", "StoreAddress": "〒276-0049 千葉県八千代市緑ヶ丘２－１－３　２Ｆ", i can parse correctly all of them

Jens Over a year ago

Yeah, the example JSON appears to be correctly formatted (by adding the missing {} required to make it a JSON object) - so it seems your actual input is invalid. If you are getting the JSON from an externally available source you should consider running it through an on-line validator, such as this.

Sergey Benner · Accepted Answer · 2012-02-14 13:14:19Z

1

well it worked here:

 String json = "{\"1\": [{\"StoreName\": \"イオン八千代緑が丘店\",\"StoreTel\": \"047-480-          3660\"," +
                "\"StoreAddress\": \"〒276-0049 千葉県八千代市緑ヶ丘２－１－３　２Ｆ\"," +
                "\"WorkingTimeInNormalDay\": \"7:30 AM - 9:00PM\"," +
                "\"WorkingTimeInWeekend\": \"9:00-22:00\"," +
                "\"HaveKidProduct\": \"N\"" +
                "}]}";


            try {
                JSONObject e = new JSONObject(json);
                JSONArray jArray = e.getJSONArray("1");
                 for(int i=0;i<jArray.length();i++){
                JSONObject obj = jArray.getJSONObject(i);
                 System.out.println(obj.getString("WorkingTimeInNormalDay"));
                }

                System.out.println(jArray.getString(0));
            } catch (JSONException e) {
                Log.e("log_tag", "Error parsing data " + e.toString());
            }

answered Feb 14, 2012 at 13:14

Sergey Benner

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1 Comment

Sergey Benner Over a year ago

I did not escape it if you look more carefully. I did not escape the : sign. I escaped the double quotes.

Drejc · Accepted Answer · 2012-02-14 13:27:36Z

1

Take a look at the Google GSON library for Android. You can with ease add your own parsers for specific data types.

For instance:

public class DateDeserializer implements JsonDeserializer<Date>
{
    public Date deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException
    {
        String JSONDateToMilliseconds = "\\/(Date\\((.*?)(\\+.*)?\\))\\/";
        Pattern pattern = Pattern.compile(JSONDateToMilliseconds);
        Matcher matcher = pattern.matcher(json.getAsJsonPrimitive().getAsString());
        String result = matcher.replaceAll("$2");

        return new Date(new Long(result));
    }
}

answered Feb 14, 2012 at 13:27

Drejc

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1 Comment

Sergey Benner Over a year ago

but that will make you package that library with your apk instead of just using the native one.

Nam Vu · Accepted Answer · 2012-02-14 13:25:33Z

0

Oh, there is no problems with ":" character.

There is a my big mistake.

Everything is work well

Sorry

answered Feb 14, 2012 at 13:25

Nam Vu

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