2D array in file/program scope

Question

I need an array which I can access from different methods, I have to allocate this array in main() and then let other functions like foo() get access to this array.

This question helped me with allocating the array: defining a 2D array with malloc and modifying it
I'm defining the array like this: char(*array)[100] = malloc((sizeof *array) * 25200); And I'm doing this in main()
I can store 25200 strings in this array an access them by array[1]

Is it now possible to access this array from different methods, how can I do that?

ouah · Accepted Answer · 2012-02-14 17:07:35Z

1

With this declaration:

char (*array)[100] = malloc((sizeof *array) * 25200);

You can have a function foo:

void foo(char array[][100])
{
    array[42][31] = 'A';  // you can access characters elements this way
    strcpy(array[10], "Hello world\n");  // you can copy a string this way
}

and you can call foo this way:

foo(array);

edited Feb 14, 2012 at 17:07

answered Feb 14, 2012 at 17:01

ouah

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4 Comments

Joelmob Over a year ago

Maybe i should have added i have to malloc it in main()

ouah Over a year ago

@Joelmob Does it change something?

Joelmob Over a year ago

this is working good but is it possible without needing to have inparameter to foo()

ouah Over a year ago

@Joelmob you can declare char (*array)[100] at file scope, malloc it in your main and directly use it in a foo function that takes no parameter; this will work but it is bad style.

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