PHP input text with variables

Question

Consider the following code for printing questions from text file:

    foreach ($lines as $line_num => $line) {
        if($line_num%3 == 1){
            echo 'Question '.$count.':'.'<br/>'.'<input type="text" value="$line" class="tcs"/>'.'<br/>';

I've tried many string escaping combinations. The problem is that I get $line inside the text field instead of the variable value. Any help is greatly appreciated.

Are you using PHP first time?

Lion
– Lion

2012-02-14 19:25:32 +00:00
Commented Feb 14, 2012 at 19:25 — Lion
– Lion, Commented Feb 14, 2012 at 19:25

Fosco · Accepted Answer · 2012-02-14 19:22:10Z

3

Remove the variable from the ' quoted string, or use " so the variable is interpreted.

echo 'Question ' . $count . ':<br/><input type="text" value="' . $line . '" class="tcs"/><br/>';

or

echo "Question " . $count . ":<br/><input type=\"text\" value=\"$line\" class=\"tcs\"/><br/>";

The first option is better, since you don't have to escape anything else.

answered Feb 14, 2012 at 19:22

Fosco

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calebds · Accepted Answer · 2012-02-14 19:22:03Z

2

Did you try:

echo 'Question ' . $count . ':'.'<br/>'.'<input type="text" value="' . $line . '" class="tcs"/>'.'<br/>';

answered Feb 14, 2012 at 19:22

calebds

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animuson · Accepted Answer · 2012-02-14 19:22:23Z

2

Variables don't get processed in single quoted strings. You need to use double quotes or another way of inserting them (such as concatenation).

answered Feb 14, 2012 at 19:22

animuson♦

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