regex match bash variable

Question

I am trying to modify a bash script. The script current contains

print "<div class=\"title\">" $1 "</div>"

Where $1 may look like:

Apprentice Historian (Level 1)
Historian (Level 4)
Master Historian (Level 7)

What i'd like to do is add an image which is named the "base" value. I had something like this in mind:

print "<div class=\"icon\"><imgsrc=\"icons\" $1 ".png\"></div><div class=\"title\">" $1 "</div>"

However, in this case I'd like $1 to only return Historian. I was thinking I could use a regex to match and on $1 and keep only the part I need.

(Apprentice|Master)?\s(.*)\s(\(Level \d\))

I know my regex isn't quite there, ideally apprentice/master would be in their own match group and not tied the base. And I don't know how to match on the $1 argument.

Thanks for the link but I'm not actually parsing [x]html. I'm actually creating an html output based on a few keywords. — Brombomb
– Brombomb, Commented Feb 15, 2012 at 7:13
@JackManey I think the OP asks to regex the Apprentice Historian (Level 1) kind of string using bash. — bezmax
– bezmax, Commented Feb 15, 2012 at 7:13

choroba · Accepted Answer · 2012-02-16 08:28:23Z

9

Using regex matching in bash:

for a in 'Apprentice Historian (Level 1)' 'Historian (Level 4)' 'Master Historian (Level 7)' ; do
    set "$a"
    echo " === $1 ==="
    [[ $1 =~ (Apprentice|Master)?' '?(.*)' ('Level' '[0-9]+')' ]] \
        && echo ${BASH_REMATCH[${#BASH_REMATCH[@]}-1]}
done

The tricky part is to retrieve the correct member from BASH_REMATCH. Bash does not support non-capturing parentheses, therefore Historian is either under 1 or 2. Fortunately, we know it is the last one.

edited Feb 16, 2012 at 8:28

answered Feb 15, 2012 at 11:51

choroba

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user unknown · Accepted Answer · 2012-02-15 10:00:12Z

5

Samples pure shell:

a="Historian (Level 1)"
noParens=${a/ \(*/}
lastWord=${noParens/[A-Za-z]* /}

a="Muster Historian (Level 1)"
noParens=${a/ \(*/}
lastWord=${noParens/[A-Za-z]* /}

(It's the same expressions in both cases, just repeated for easy testing).

answered Feb 15, 2012 at 10:00

user unknown

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Comments

Kristofer · Accepted Answer · 2012-02-15 07:30:57Z

0

Based on "And I don't know how to match on the $1 argument."

Have I understood you correctly if what you are asking for is not whether your regex is correct but rather how to perform the match against the contents of your bash variable?

matched_text=$(echo $yourbashvariablecontainingthetext | sed 's/your_regex/backreference_etc/')

$yourbashvariablecontainingthetext should be your $1

answered Feb 15, 2012 at 7:30

Kristofer

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