using grep to parse output from another command

Question

after doing the command in the terminal: forever list

i get the following output:

info:   Forever processes running
data:       uid  command script           forever pid logfile                              uptime        
data:   [0] 0ClV node    enfomo-server.js 376     377 /Users/USERNAME/.forever/0ClV.log 0:0:37:26.987

i need to use grep or some alternative to give as output the following string only:

/Users/USERNAME/.forever/0ClV.log

what is the proper command?

Kai Sternad · Accepted Answer · 2012-02-17 19:17:45Z

3

You can do this with grep using the -o flag which only prints the matching part:

forever list | grep -o '\/Users.*log'

answered Feb 17, 2012 at 19:17

Kai Sternad

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3 Comments

Paul Beckingham Over a year ago

Note: this approach relies on the content, rather than the position. This may be ideal, or it may be limited, depending on the data, which is not characterized.

Kai Sternad Over a year ago

Thank you Paul for pointing this out, I interpreted the question as being dependent on content.

user1082013 Over a year ago

ahh. was a character or two off in my regex.

Paul Beckingham · Accepted Answer · 2012-02-17 19:12:07Z

2

First you might want to isolate only the lines you want with grep, then awk would work:

grep node file | awk '{print $7}'

or cut:

grep node file | cut -d\  -f7

answered Feb 17, 2012 at 19:12

Paul Beckingham

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