java server socket

Question

i wanted to create a java server and client in a same file...because this is my structure of project

SERVER ---> CLIENT/SERVER ----> CLIENT

the coding for the SERVER and CLIENT part is quite simple but i have a problem when creating for CLIENT/SERVER part.. where my code can only run CLIENT part and not starting the SERVER part. because of my thread run() code.

package com.main.datadistributor;

    import java.io.IOException;
    import java.net.ServerSocket;

    public class Slave {
        public static void main(String args[]) throws IOException{
        Config cfg = new Config("Slave");
        String MasterServerIP = cfg.getProperty("MasterServerIP");
        String MasterServerPort = cfg.getProperty("MasterServerPort");
        String SlaveServerPort = cfg.getProperty("SlaveServerPort");

        Client client = new Client(MasterServerIP,Integer.parseInt(MasterServerPort),"SLAVEONE");
        client.run();

        int numClient = 0;
        ServerSocket listener = new ServerSocket(Integer.parseInt(SlaveServerPort));
        System.out.println("Server starts running");

        try{
            while(true){
                new Server(listener.accept(), numClient++, Integer.parseInt(SlaveServerPort), "SLAVESERVER").start();
            }
        } finally {
            listener.close();
        }


    }
}

from the code above i have problem only executing client.run() and the code just stop there without proceeding to execute new Server below at the try section

What is client.run(); ? Why not a thread for this thing too ? — nIcE cOw
– nIcE cOw, Commented Feb 18, 2012 at 4:58

Jim Garrison · Accepted Answer · 2012-02-18 04:58:11Z

2

If Client subclasses Thread, then you need to call start(), not run(). If it implements Runnable then you need to instantiate a Thread to execute it and call the thread's start() method.

answered Feb 18, 2012 at 4:58

Jim Garrison

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Comments

cutchin · Accepted Answer · 2012-02-18 04:57:35Z

1

Not knowing what Client is, or seeing its code limits our ability to help. If it has a run() method it may implement Runnable, so you can possibly just call new Thread(client).start() instead of calling its run method directly.

answered Feb 18, 2012 at 4:57

cutchin

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