php array values matched again arrays keys

Question

I have an string in database : 3,8,10,15

and in script i have an array : $a=array(0=>'music',1=>'computers'....etc), the keys are matching the strings in database.

Then i explode() the string from database with: $a=explode(",",$dbresult) This makes an array like this:

$a =
Array
(
    [0] => 3
    [1] => 8
    [2] => 10
    [3] => 15
)

In script:

<?PHP
$b=array(0=>'music',1=>'Computers','...etc');
    $a = explode(",",$a);
    foreach ( $b as $key => $value ){

    $select = $a==$key ? " checked='checked'" : null;

    echo "<label><input type='checkbox' name='name' value='{$key}'$select/> {$value};
    }}
?>

This ofcourse will not work since its matching the $b arrays keys, and not the values of $a

So my question is.. How can i make it match the $b keys against $a values ?

I'm not understanding the relationship to $a and $b. Are the keys supposed to align between them such that $a[0] (3) is related to $b[0] (music)? — Michael Berkowski
– Michael Berkowski, Commented Feb 19, 2012 at 1:18
Or do the values of $a relate to the keys of $b such that $a[0] (3) relates to $b[3] ('someotherthing')? — Michael Berkowski
– Michael Berkowski, Commented Feb 19, 2012 at 1:19

phihag · Accepted Answer · 2012-02-19 01:18:20Z

1

You're looking for in_array:

<?php
$b = array(0=>'music',1=>'Computers','...etc');
$a = explode(",", '0,3');
foreach ($b as $key => $value) {
    $select = in_array($key, $a) ? " checked='checked'" : null;

    echo '<input type="checkbox" name="name" value="' . $key . '"' . $select . '/>';
    echo $value;
}

answered Feb 19, 2012 at 1:18

phihag

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