Find XPATH with namespace based on attribute element

Question

I have the following xml:

<assets>
    <asset type="full">
        <file_name>WME__HD_2CH_EN_16X9_178_2398_FINAL.mov</file_name>
    </asset>
    ...
</assets>

I have multiple asset blocks, so I need to reference the attribute type = "full". This is what I currently have to reference them all --

node.xpath("//t:assets/t:asset/t:file_name/text()", 
            namespaces={'t':'http://apple.com/itunes/importer'})

How would I reference only the asset with type = "full" ?

Michael Berkowski · Accepted Answer · 2012-02-19 23:41:40Z

2

You can add the [@type="full"] attribute selector onto t:asset:

node.xpath("//t:assets/t:asset[@type='full']/t:file_name/text()", 
        namespaces={'t':'http://apple.com/itunes/importer'})

answered Feb 19, 2012 at 23:41

Michael Berkowski

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Comments

RanRag · Accepted Answer · 2012-02-19 23:42:50Z

1

Try this

node.xpath("//t:assets/t:asset[@type='full']/t:file_name/text()", 
        namespaces={'t':'http://apple.com/itunes/importer'})

@ notation is used to select attributes through xpath.

So, t:asset[@type='full'] means select all asset element that have attribute type and value full.

Take a look here xpath synatx.

answered Feb 19, 2012 at 23:42

RanRag

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David542 · Accepted Answer · 2012-02-19 23:41:59Z

0

node.xpath("//t:assets/t:asset[@type='full']/t:file_name/text()", 
        namespaces={'t':'http://apple.com/itunes/importer'})

answered Feb 19, 2012 at 23:41

David542

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