I'd like to check if some variable is defined in R - without getting an error. How can I do this?
My attempts (not successful):
> is.na(ooxx)
Error: object 'ooxx' not found
> is.finite(ooxx)
Error: object 'ooxx' not found
Thanks!
You want exists():
R> exists("somethingUnknown")
[1] FALSE
R> somethingUnknown <- 42
R> exists("somethingUnknown")
[1] TRUE
R>
exists(quote(ooxx))if you are inside a function, missing() is what you want.
exchequer = function(x) {
if(missing(x)){
message("x is missing… :-(")
}
}
exchequer()
x is missing… :-(
As others have pointed out, you're looking for exists. Keep in mind that using exists with names used by R's base packages would return true regardless of whether you defined the variable:
> exists("data")
[1] TRUE
To get around this (as pointed out by Bazz; see ?exists), use the inherits argument:
> exists("data", inherits = FALSE)
[1] FALSE
foo <- TRUE
> exists("foo", inherits = FALSE)
[1] TRUE
Of course, if you wanted to search the name spaces of attached packages, this would also fall short:
> exists("data.table")
[1] FALSE
require(data.table)
> exists("data.table", inherits = FALSE)
[1] FALSE
> exists("data.table")
[1] TRUE
The only thing I can think of to get around this -- to search in attached packages but not in base packages -- is the following:
any(sapply(1:(which(search() == "tools:rstudio") - 1L),
function(pp) exists(_object_name_, where = pp, inherits = FALSE)))
Compare replacing _object_name_ with "data.table" (TRUE) vs. "var" (FALSE)
(of course, if you're not on RStudio, I think the first automatically attached environment is "package:stats")
inherits = FALSE seems to isolate things in the global environment. Does that sound right?If you don't want to use quotes, you can use deparse(substitute()) trick which I found in the example section of ?substitute:
is.defined <- function(sym) {
sym <- deparse(substitute(sym))
env <- parent.frame()
exists(sym, env)
}
is.defined(a)
# FALSE
a <- 10
is.defined(a)
# TRUE
force or evaluate it in the function like this: is.defined <- function(sym) class(try(sym, TRUE))!='try-error'NULL for quosure (enquo(x) if x is not null), you need a good way to check if the expression passed in is not null. Your solution does exactly that. thanksIf you don't mind using quotes, you can use:
exists("x")
If you don't want to use quotes you can use:
exists(deparse(substitute(x)))
There may be situations in which you do not exactly know the name of the variable you are looking for, like when an array of results have been created by a queuing system. These can possibly be addressed with "ls" and its argument "pattern" that expects a regular expression.
The "exists" function could be reimplemented that way as
exists <-function(variablename) {
#print(ls(env=globalenv()))
return(1==length(ls(pattern=paste("^",variablename,"$",sep=""),env=globalenv())))
}
While preparing this answer, I was a bit surprised about the need for the need of the specification of the environment when invoking ls() from within a function. So, thank you for that, stackoverflow! There is also an "all.names" attribute that I should have set to true but have omitted.