Extract a complex String from between two Strings [duplicate]

Question

I have a String which contains the following sub string:

[Qual:3] [Text:PIX 1252471471953/YHYF/PPP121.40/10RTY10/NOLXX08X1] [Elem:123]

I'd like to extract the part between [Text: and ] i.e. PIX 1252471471953/YHYF/PPP121.40/10RTY10/NOLXX08X1.

How do I do this?

Use String.substring(int, int) and String.indexOf(String, int) — mcfinnigan
– mcfinnigan, Commented Feb 21, 2012 at 15:06
I've been trying variations on the suggestions here stackoverflow.com/questions/1216601/… — mip
– mip, Commented Feb 21, 2012 at 15:49

beerbajay · Accepted Answer · 2012-02-21 15:10:30Z

4

Pattern p = Pattern.compile("\\[Text:(.*?)\\]");
Matcher m = p.matcher("[Qual:3] [Text:PIX 1252471471953/YHYF/PPP121.40/10RTY10/NOLXX08X1] [Elem:123]");
m.find();
System.out.println(m.group(1));

Gives:

PIX 1252471471953/YHYF/PPP121.40/10RTY10/NOLXX08X1

The \\[ and \\] are to escape the brackets, which are special characters in regexes. The .*? is a non-greedy quantifier, so it stops gobbling up characters when it reaches the closing bracket. This part of the regex is given inside a capturing group (), which you can access with m.group(1).

answered Feb 21, 2012 at 15:10

beerbajay

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Comments

NPE · Accepted Answer · 2012-02-21 15:08:20Z

2

Use the following string as the regex:

"\\[Text:(.*?)\\]"

The first capture group will give you exactly the substring you want.

The non-greedy match (.*?) is required to make it stop at the first ] rather than also including [Elem:123].

answered Feb 21, 2012 at 15:08

NPE

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1 Comment

Alex D Over a year ago

Beat me to it! +1. @mip, note the difference between .*? and .*. One of the commenters suggested .*, but that doesn't work; it doesn't stop where it should.

garyamorris · Accepted Answer · 2012-02-21 15:09:46Z

0

String.substring(int beginIndex, int endIndex)

Returns a new string that is a substring of this string.

You could use this to remove the start and end of the string,

or....

You could use

String.indexOf(String str)

To get the index of the start and end of the match and copy the contents to a new result string.

You could use

String.matches(String regex)

However writing regular expressions can get difficult,

http://docs.oracle.com/javase/6/docs/api/java/lang/String.html

I hope this helps.

answered Feb 21, 2012 at 15:09

garyamorris

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Comments

GenericJon · Accepted Answer · 2012-02-21 15:16:59Z

0

Instead of using "\\[Text:(.*?)\\]", as others have suggested, I'd go one step further and use lookarounds to filter out the text you don't want:

(?<=\\[Text:).*?(?=\\])

This will match exactly the text you want without having to select a capturing group.

answered Feb 21, 2012 at 15:16

GenericJon

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1 Comment

mip Over a year ago

thanks for that. What would the Java look like? Would I replace m.find and m.group(1)?

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