PHP replacing all occurances of certain string pattern in HTML formatted text

Question

I have input text that can be long HTML text with tags and so on. Example of input can be something like:

<p>Lorem ipsum dolor sit amet, <strong>consectetur</strong> adipiscing elit.<p>
<p>%image1%</p>
<h2>Lorem ipsum</h2>
<p>Cum sociis natoque penatibus et magnis dis parturient montes.</p>
<p>%image2%</p>
<p>Lorem ipsum dolor sit amet, consectetur adipiscing elit. </p>
<p>%image3%</p>
<p>Lorem ipsum dolor sit amet, consectetur adipiscing elit. </p>
...

What would be the easiest way of finding all occurrences of text between %% characters and replacing that with <img src="image1.jpg">?

Word of warning: The current trend is 10% in comparison to 5% last year. %graph1% (Either don't allow a space after % or prepare for some trouble with <img src=" in comparison to 5.jpg"> — Alexander Varwijk
– Alexander Varwijk, Commented Feb 24, 2012 at 15:10
I don't quite understand this comment? Can you please explain? — Primoz Rome
– Primoz Rome, Commented Feb 24, 2012 at 15:41
BTW: I can force something else then %image1% to users who will use this? Should I use #iamge1# or something else instead? — Primoz Rome
– Primoz Rome, Commented Feb 24, 2012 at 15:43
What I mean, is that if you have a string that contains two of your selection characters, '%' in this case you will select the text in between those characters and might unintentionally add an image where you don't want one. — Alexander Varwijk
– Alexander Varwijk, Commented Feb 24, 2012 at 15:49

Churk · Accepted Answer · 2012-02-24 15:11:09Z

1

try using preg_replace ('/%(.+?)%/', '<img src="image1.jpg">', $string); i might be a little bit off on the regex pattern as to rather u need to escape %, and if ? is the greedy symbol.

answered Feb 24, 2012 at 15:11

Churk

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Madara's Ghost Over a year ago

-1. Would explode on %image1% text %image2%. It will create only one image.

Vytautas · Accepted Answer · 2012-02-24 15:19:49Z

0

preg_replace('|%(.+)%|', '<img src="$1">', $text );

working example: http://codepad.org/20Oz3Vok

answered Feb 24, 2012 at 15:19

Vytautas

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Primoz Rome Over a year ago

Is there a way to replace every occurrence separately? Because I need to see what's the value between %% and then accordingly to this find the right image in DB and put it in...!

Madara's Ghost · Accepted Answer · 2012-02-24 15:16:25Z

-1

Try this:

preg_replace('|%(\w+)%|', '<img src="$1">', $string);

It will only allow alphanumeric characters, as well as underscores (to prevent the problem @AlexanderVarwijk pointed out in the comments).

answered Feb 24, 2012 at 15:16

Madara's Ghost

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1 Comment

Madara's Ghost Over a year ago

of course it will. \w matches alphanumeric characters, plus underscores. Thats [a-zA-Z0-9_],

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