Getting a Perl command output into a shell variable

Question

I'm a bit of a noob with Perl, and can't to see what's wrong with this script:

#!/bin/sh
randAnPass=true;
if [ $randAnPass = true ]
then
pass=perl /root/bin/randpass
else
# prompt for setting user's password ..
echo -n "pick password for '${user}': "
read pass
fi
#echo $randAnPass;
echo "Generated pass = $pass";

For some reason it outputs:

r4Nd0mP
Generated pass =

I want it to output

Generated pass = r4Nd0mP

Use backticks to capture command output, you're just running the command. — Dave Newton
– Dave Newton, Commented Feb 26, 2012 at 1:30
I don't see how it can be much better, but sure, that works too. — Dave Newton
– Dave Newton, Commented Feb 26, 2012 at 1:32
That worked :D probably should've been an answer lol cause.. well it is the answer :P. Thanks very much. :) — Goulash
– Goulash, Commented Feb 26, 2012 at 1:33
@DaveNewton - I am not sure of the benefits, so I asked :) stackoverflow.com/questions/9449778/… — DVK
– DVK, Commented Feb 26, 2012 at 1:38

Shiplu Mokaddim · Accepted Answer · 2012-02-26 09:48:48Z

5

If you want to just capture STDOUT of perl command use,

pass=$(perl /root/bin/randpass)

But if you need to capture both STDERR and STDOUT,

pass=$(perl /root/bin/randpass 2>&1)

edited Feb 26, 2012 at 9:48

answered Feb 26, 2012 at 1:41

Shiplu Mokaddim

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DVK · Accepted Answer · 2012-02-26 01:33:07Z

4

pass=`perl /root/bin/randpass`

answered Feb 26, 2012 at 1:33

DVK

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