python string replace digits

Question

I am trying to replace certain parts of the string below.

'''<td align="center"> 5 </td> <td> align="center"> 0.0001 </td>'''

I need to remove the <td> tag if there is a '0.'(decmial occurrence). i.e. the output should be

'''<td align="center"> 5 </td>'''

I have tried this

data = ' '.join(data.split())<br>
l = data.replace('<td align="center"> 0.r"\d" </td>', "")

but didn't succeed. Could anyone please help me with doing this.

Thanks in advance

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– Cris Stringfellow, Commented Feb 28, 2012 at 10:14

Kimvais · Accepted Answer · 2012-02-28 10:49:58Z

11

While both of the regular expression examples work, I would advice against using regexp.

Especially if the data is a full html document, you should go for html-aware parser, such as lxml.html e.g.:

from lxml import html
t = html.fromstring(text)
tds = t.xpath("table/tbody/tr[2]/td")
for td in tds:
    if tds.text.startswith("0."):
        td.getparent().remove(td)
text = html.tostring(t)

edited Feb 28, 2012 at 10:49

answered Feb 28, 2012 at 10:10

Kimvais

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zeroos · Accepted Answer · 2012-02-28 09:56:34Z

2

I would do it with regular expression:

import re
s = "<td align='center'> 5 </td><td align='center'>0.00001</td>"
re.sub("<td align='center'>0.\d+</td>", "", s)

answered Feb 28, 2012 at 9:56

zeroos

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Darth Plagueis · Accepted Answer · 2012-02-28 10:05:24Z

2

You could use a regular expression to check for the <td> and if it matches, you can use re.sub() to replace it with what ever you want.

pattern = '\"<td align=\"center\"> 0.[0-9]+ </td>\"'
p = re.compile(pattern)
p.sub('', my_string)

where my_string contains the string you want to operate on, hope this helps

edited Feb 28, 2012 at 10:05

answered Feb 28, 2012 at 9:57

Darth Plagueis

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