Bash String extraction

Question

I have a really easy problem that I am not able to solve quickly. I must extract a substring from something like this:

a="www.himom.com/byebye"

I want to retrieve this:

"/byebye"

Actually, I am able to retrieve

"www.himom.com" with

echo ${a%/*}

Any suggestions?

Ivaylo Strandjev · Accepted Answer · 2012-02-28 16:09:29Z

3

Try this: echo /${a##*/} It deletes the longest substring ending at '/'.

answered Feb 28, 2012 at 16:09

Ivaylo Strandjev

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Comments

Jamie · Accepted Answer · 2012-02-28 16:08:57Z

3

Try this:

 a="www.himom.com/byebye"; echo "/${a##*/}"

answered Feb 28, 2012 at 16:08

Jamie

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2 Comments

Ivaylo Strandjev Over a year ago

You will be missing the '/' character that he wants to get.

GreenMatt Over a year ago

@izomorphius: Maybe the poster edited the answer, but what I see worked on my machine.

glenn jackman · Accepted Answer · 2012-02-28 20:10:52Z

1

To leave the slash in the string

shopt -s extglob
echo "${a##*([^/])}"

answered Feb 28, 2012 at 20:10

glenn jackman

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Comments

Brian Mains · Accepted Answer · 2012-02-28 17:23:19Z

0

$ a="www.himom.com/byebye" | echo ${a##*m}
/byebye

edited Feb 28, 2012 at 17:23

Brian Mains

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answered Feb 28, 2012 at 17:13

lina

1

Comments

Brian Mains · Accepted Answer · 2012-02-28 17:23:26Z

0

I am a lazy guy.. Solution was:

${a##*/}

edited Feb 28, 2012 at 17:23

Brian Mains

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answered Feb 28, 2012 at 16:09

pedr0

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1 Comment

GreenMatt Over a year ago

Sorry for the multiple edits/rollbacks. I tried to get the code to show correctly, but what I tried didn't work.

GreenMatt · Accepted Answer · 2012-02-28 16:19:59Z

-1

You can extract your desired substring with a regex:

a="www.himom.com/byebye"
echo `expr match "$a" '.*\(\/.*\)'`

answered Feb 28, 2012 at 16:19

GreenMatt

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