Getting the parent node attributes in XSL

Question

In my XML I have the following:

<a>
  <b>
    <c something="false">
      <d>
        <e>
          <f>someResult</f>
        </e>
      </d>
    </c>
  </b>
</a>

Now in the XSL within a loop I can do the following:

<xsl:value-of select="f"></xsl:value-of>

But how can I get the attribute in c?

I've tried doing the following

<xsl:value-of select="////@something"></xsl:value-of>

As well as trying parent and nothing seems to be working. Can you get parent nodes like this?

Also, I cannot just do:

<xsl:value-of select="/a/b/c/@something"></xsl:value-of>

As there can be multiple of c.

demongolem · Accepted Answer · 2013-05-01 17:46:07Z

52

To move up the tree you use ".." per level ie in this instance probably

select="../../../@something"

You can also select an ancestor node by name (approx)

select="ancestor::c[1]/@something"

See http://www.stackoverflow.com/questions/3672992 for further examples

edited May 1, 2013 at 17:46

demongolem

9,76436 gold badges97 silver badges107 bronze badges

answered Feb 28, 2012 at 16:25

kaj

5,2712 gold badges23 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Dimitre Novatchev · Accepted Answer · 2012-02-28 17:08:35Z

12

Use:

ancestor::c[1]/@something

This selects the attribute named something of the first (from the current node upwards) ancestor named c.

answered Feb 28, 2012 at 17:08

Dimitre Novatchev

244k27 gold badges307 silver badges438 bronze badges

1 Comment

Dimitre Novatchev Over a year ago

@AkashTantri, no, ancestor::c is the node-list of all ancestor nodes that are named "c". ancestor::c[1] selects the nearest "c" ancestor of the current node.

Collectives™ on Stack Overflow

Getting the parent node attributes in XSL

2 Answers 2

Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related