I have this string:
'2012-02-10' # (year-month-day)
and I need it to be as date type for me to use the date function isoweekday().
Does anyone know how I can convert this string into a date?
-
1This would help for someone who also needs all date and time: > datetime.datetime.strptime('2020-10-13 00:00:00', '%Y-%m-%d %H:%M:%S')Han Van Pham– Han Van Pham2020-12-14 08:40:18 +00:00Commented Dec 14, 2020 at 8:40
Add a comment
|
5 Answers
While it seems the question was answered per the OP's request, none of the answers give a good way to get a datetime.date object instead of a datetime.datetime. So for those searching and finding this thread:
datetime.date has no .strptime method; use the one on datetime.datetime instead and then call .date() on it to receive the datetime.date object.
Like so:
>>> from datetime import datetime
>>> datetime.strptime('2014-12-04', '%Y-%m-%d').date()
datetime.date(2014, 12, 4)
3 Comments
Nyxynyx
This is the real answer
liamsuma
This should be the accepted answer
SQA777
If I convert the datetime.datetime object to a datetime.date object, the datetime.date object doesn't work with the datetime.timedelta() method. Is there a way to do date calculations (such as add or subtract days from a date) if the object is datetime.date?
You can do that with datetime.strptime()
Example:
>>> from datetime import datetime
>>> datetime.strptime('2012-02-10' , '%Y-%m-%d')
datetime.datetime(2012, 2, 10, 0, 0)
>>> _.isoweekday()
5
You can find the table with all the strptime directive here.
To increment by 2 days if .isweekday() == 6, you can use timedelta():
>>> import datetime
>>> date = datetime.datetime.strptime('2012-02-11' , '%Y-%m-%d')
>>> if date.isoweekday() == 6:
... date += datetime.timedelta(days=2)
...
>>> date
datetime.datetime(2012, 2, 13, 0, 0)
>>> date.strftime('%Y-%m-%d') # if you want a string again
'2012-02-13'
5 Comments
Lucas Rezende
That was exactly what I did: if datetime.strptime(a, "%Y-%m-%d").isoweekday() == 6: PONTO_MOVIMENTO = a
Lucas Rezende
Just one more question... how can I add days to my date? For example, if isoweekdday() == 6, i need to increment the date in 2 days. Have idea how I do that? Thanks again!
Lucas Rezende
I found out already using timedelta. But thanks!
Rik Poggi
@user1072627: Yes
timdelta is the right tool. Even though you've already found it I added an example anyway. :)
Jonathan Rys
This converts a string to a datetime. The OP asked how to convert a string to a date. If I print your converted datetime I get
2012-02-13 00:00:00 which is not a date and does not match the format specified in strptime.from datetime import datetime
a = datetime.strptime(f, "%Y-%m-%d")
Comments
Use datetime.datetime.strptime:
>>> import datetime
>>> date = datetime.datetime.strptime('2012-02-10', '%Y-%m-%d')
>>> date.isoweekday()
5
Comments
>>> from datetime import datetime
>>> year, month, day = map(int, my_date.split('-'))
>>> date_object = datetime(year, month, day)
1 Comment
CraigO
I used something like this when I needed a datetime.date object, NOT a datetime.datetime object. Unfortunately, datetime.date does not have a strptime() method.