add php var within url parameter

Question

Current URL is

<?php include ("/home/domain/public_html/create/dogs.php"); ?>

I want to do this:

<?php include ("/home/domain/public_html/create/<?php $partURL; ?>s.php"); ?>

$partURL is predefined. Just need to parse the php include within the above URL to parse correctly

Muhit · Accepted Answer · 2012-03-01 02:59:37Z

2

You can do like this

 <?php include ("/home/domain/public_html/create/{$partURL}s.php"); ?>

You can not use php tag with in a php tag like <?php <?php ?>?>

answered Mar 1, 2012 at 2:59

Muhit

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Comments

Aaron W. · Accepted Answer · 2012-03-01 03:00:07Z

1

Read up on strings in PHP.

<?php include ("/home/domain/public_html/create/".$partURL."s.php"); ?>

answered Mar 1, 2012 at 3:00

Aaron W.

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Comments

Arjun Bajaj · Accepted Answer · 2012-03-01 03:00:45Z

1

You have to remove the PHP Tags from the "part URL" cause you are already in PHP.

<?php include ("/home/domain/public_html/create/" . $partURL . "s.php"); ?>

answered Mar 1, 2012 at 3:00

Arjun Bajaj

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1 Comment

Arjun Bajaj Over a year ago

remember, his version will only work till you have double quotes around the string, if you go for single quotes, you will have to use this method. So dont forget that. and, welcome. :D

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