i seen to be having a problem with the line:
int xPos = ((x / maxX) * X_AXIS_LENGTH) + X_AXIS_OFFSET; =
for testing purposes i have assigned:
int x = 10;
int maxX = 52;
but when used in this calculation x / maxX gives me 0 instead of 0.19!
You're doing integer division here:
x / maxX
Integer division will truncate the fractional part.
Cast one of the parameters to floating-point to fix it:
(double)x / maxX
You might also want to store the whole thing into a double instead of int:
double xPos = (((double)x / maxX) * X_AXIS_LENGTH) + X_AXIS_OFFSET;
Both of the operands for / are integers, so it's performing integer arithmetic. Options:
Use floating point arithmetic:
double xPos = (((double) x / maxX) * X_AXIS_LENGTH) + X_AXIS_OFFSET;
Multiply before the division, and you can still do everything in integer arithmetic, although you'll need to beware of overflow:
int xPos = ((x * X_AXIS_LENGTH) / maxX) + X_AXIS_OFFSET;
Integer division did it to you.
If you expect a floating point value, do it this way:
double ratio = ((double)x)/maxX;
That int type all the way though is a problem. I'd put more thought into that. Where do you want to truncate the fractional part?
xPos should be declared as double, not an integer. Otherwise, the data after the decimal point is truncated.
