PHP check for instance of DateTime?

Question

Is this the only way to check if an object is an instance of a class, in my case of the DateTime class?

$cls = ReflectionClass("DateTime");
if (! $cls->isInstance( (object) $var ) ) {
    // is not an instance
}

It seems a bit heavy to me.

See as well: How to know what class is an object instance of? (php5) (Not really a duplicate) — hakre
– hakre, Commented Mar 5, 2012 at 15:48

Baby · Accepted Answer · 2014-04-14 06:32:57Z

161

You could try instanceof^Docs...

if ($var instanceof DateTime) {
  // true
}

1 Comment

Niklas R Over a year ago

Man, I didn't find anything about that one with google .. :/ Thank you!

Distdev · Accepted Answer · 2012-03-05 15:03:49Z

10

if ($var instanceof DateTime)

answered Mar 5, 2012 at 15:03

Distdev

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Comments

botzko · Accepted Answer · 2012-03-05 15:08:12Z

7

You can use get_class function like this:

<?php

    $a = new DateTime();
    if (get_class($a) == 'DateTime') {
        echo "Datetime";
    }

answered Mar 5, 2012 at 15:08

botzko

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1 Comment

Chadwick Meyer Over a year ago

@redolent If you are using Symfony or some other framework that uses namespaces, you may need to declare use \DateTime at the top of your file to make it look for DateTime in the root namespace (not your app's namespace).

rkosegi · Accepted Answer · 2012-03-05 15:06:41Z

5

What about instanceof

answered Mar 5, 2012 at 15:06

rkosegi

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