Php array output confusion

Question

In PHP when I do

var_dump($galleryCategoriesThumb);

Output is

    array(1) {


[0]=>
  array(1) {
    ["Gallery"]=>
    array(3) {
      ["id"]=>
      string(3) "190"
      ["photofile"]=>
      string(6) "50.jpg"
      ["gallery_category_id"]=>
      string(2) "58"
    }
  }
}

When I do

var_dump($galleryCategoriesThumb["photofile"]);

I get NULL output. I tried various other options also. All I want to do is echo ["photofile"]. Please help.

sandeep · Accepted Answer · 2012-03-06 06:09:26Z

3

Try $galleryCategoriesThumb[0]['Gallery']["photofile"]

answered Mar 6, 2012 at 6:09

sandeep

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user978548 · Accepted Answer · 2012-03-06 06:20:12Z

1

Try var_dump($galleryCategoriesThumb[0]["Gallery"]["photofile"]);.

It's a 3 dimensions array.

edited Mar 6, 2012 at 6:20

answered Mar 6, 2012 at 6:08

user978548

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Adrian Gunawan · Accepted Answer · 2012-03-06 07:50:24Z

1

It is expected that var_dump($galleryCategoriesThumb["photofile"]) returns NULL because "photofile" key does not exist in $galleryCategoriesThumb.

To access "photofile", you need a 'full path' in the array as posted by others

var_dump($galleryCategoriesThumb[0]["Gallery"]["photofile"]);.

answered Mar 6, 2012 at 7:50

Adrian Gunawan

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